IBIB Mathematics AA HL

IB Math AA SL & HL Geometry and Trigonometry Formulae

Master IB Math AA SL and HL geometry and trigonometry: 3D distance, solids, sine and cosine rules, radians, identities, graphs and equations.
IB Math AA SL and HL geometry and trigonometry formula map with 3D distance, triangle, circle, unit-circle and equation diagrams

IB Mathematics: Analysis and Approaches

Geometry and Trigonometry Formulae for AA SL and HL

A complete educator-written guide to the geometry and trigonometry studied by every IB Mathematics AA student: three-dimensional geometry, triangle methods, radians, circular functions, identities, graphs, modelling and finite-interval equations.

AA SL 3.1–3.8Required foundation for AA HLWorked examplesExam methodFormula selection
Scope note: this page explains the SL geometry and trigonometry content that AA SL students study and AA HL students must also master before their additional higher-level work. Reciprocal ratios, inverse trigonometric functions, compound-angle identities and vectors belong to the additional HL sequence and are signposted separately. The IB has announced a revised course for first assessment in May 2029, so students should always use the subject guide and formula booklet supplied by their school for their examination session.

Geometry and trigonometry are often presented as a list of formulas, but successful IB Mathematics AA work depends on decisions. You must turn words into a labelled diagram, identify the correct triangle or circular relationship, keep degree and radian modes under control, preserve exact values, solve within a stated interval and interpret the result in context. A formula sheet helps only after you understand what each symbol represents.

This guide develops that understanding. Each section explains the formula, the conditions under which it is valid, a reliable solution method, common errors and the link to later functions or calculus. It is designed for revision, topic repair and final exam preparation rather than last-minute memorisation.

IB Math AA SL and HL geometry and trigonometry formula map with 3D distance, triangle, circle, unit-circle and equation diagrams
Visual map of the shared IB Mathematics AA SL and HL geometry and trigonometry foundation.

What geometry and trigonometry do AA SL and HL share?

The official course structure begins Topic 3 with standard-level content. AA SL students study that content; AA HL students study it too and then continue into additional higher-level material. The shared sequence includes distance and midpoint in three dimensions, surface area and volume, angles in three-dimensional objects, right-triangle ratios, sine and cosine rules, triangle area, applications and diagram construction, radians, unit-circle definitions, exact trigonometric values, the ambiguous sine-rule case, identities, circular-function graphs, transformations, real-life models and finite-interval trigonometric equations.

That distinction matters for revision. Vectors are important in AA HL, but placing vector lines and planes inside a shared SL/HL formula list misrepresents what an SL student is expected to learn. Conversely, an HL student cannot skip the shared material. Vector geometry, calculus and complex numbers repeatedly rely on fluent trigonometry, exact values and diagram reasoning.

AA SL student

Master every shared section on this page. Practise technology and non-technology methods, exact values and clear diagram communication.

AA HL student

Master this entire foundation, then continue to reciprocal identities, inverse functions, compound-angle work and two- and three-dimensional vectors.

If prerequisite geometry is weak—Pythagoras, basic right-angle trigonometry, circle vocabulary or elementary area and volume—repair it first with the AA SL and HL prior-learning guide. Topic formulas become much easier when the underlying shapes and units are familiar.

IB Math AA geometry and trigonometry quick formula sheet

IdeaFormula or relationshipUse it when
3D distanced = √[(x2x1)2+(y2y1)2+(z2z1)2]Distance between two Cartesian points in space
3D midpointM = ((x1+x2)/2, (y1+y2)/2, (z1+z2)/2)Point halfway along a 3D segment
Pythagorasa2+b2=c2Right triangle; c is the hypotenuse
Right-triangle ratiossin θ = opposite/hypotenuse; cos θ = adjacent/hypotenuse; tan θ = opposite/adjacentA right triangle with a labelled reference angle
Sine rulea/sin A = b/sin B = c/sin CA known opposite side-angle pair; includes ambiguous case later
Cosine rulec2=a2+b2−2ab cos CSAS for a side or SSS for an angle
Triangle areaK = ½ab sin CTwo sides and their included angle
Degree-radian conversion180° = π radiansConvert angle units before using a formula or model
Arc lengths=θ is in radians
Sector areaAr2θθ is in radians
Tangent definitiontan θ = sin θ / cos θConnect the three circular functions; cos θ ≠ 0
Pythagorean identitysin2 θ + cos2 θ = 1Replace a squared ratio or find possible exact values
Double-angle sinesin 2θ = 2 sin θ cos θRewrite products or double-angle expressions
Double-angle cosinecos 2θ = cos2 θ − sin2 θ = 2cos2 θ−1 = 1−2sin2 θSelect the form matching the rest of the expression
Sinusoidal modelf(x)=a sin(b(x+c))+dAmplitude |a|, midline y=d, period 2π/|b|
Formula condition check: the sine rule requires correctly matched opposite pairs; the cosine rule needs the angle opposite the isolated side; s=rθ and A=½r²θ require radians; inverse-trig calculator output provides a reference answer that must still be placed in the requested interval.

Three-dimensional coordinates: distance, midpoint and angles

The three-dimensional distance formula is Pythagoras extended across three perpendicular coordinate directions. The differences in x, y and z form the three orthogonal components of the displacement. Squaring makes the sign of each difference irrelevant, but keeping corresponding coordinates together prevents substitution mistakes.

d = √[(x2x1)2 + (y2y1)2 + (z2z1)2]

Worked example: distance and midpoint

Let P=(−2, 1, 4) and Q=(4, 9, −2). The coordinate changes are 6, 8 and −6. Therefore PQ=√(6²+8²+(−6)²)=√136=2√34. The midpoint is ((−2+4)/2, (1+9)/2, (4−2)/2)=(1,5,1). Check the midpoint by subtracting it from each endpoint: the resulting displacement vectors have equal magnitude and opposite direction.

For an angle between a line and a plane in a solid, first identify the perpendicular projection of the line onto the plane. The original line, its projection and the perpendicular height form a right triangle. The requested angle is between the line and its projection—not automatically between the line and a vertical edge. Draw that triangle separately and then use sine, cosine or tangent.

Worked example: angle of a space diagonal

A cuboid measures 6 cm by 8 cm by 12 cm. The base diagonal is √(6²+8²)=10 cm. The space diagonal and its base projection form a right triangle with vertical height 12 cm. If α is the angle between the space diagonal and the base, tan α=12/10, so α≈50.2°. A common error is to use 6 cm or 8 cm as the adjacent side instead of the diagonal projection.

Volumes and surface areas of three-dimensional solids

Volume measures three-dimensional capacity and uses cubic units. Surface area measures exposed two-dimensional area and uses square units. Identify whether a question asks for total surface area, curved surface area, an open container or a compound solid before substituting.

SolidVolumeSurface-area facts
PrismV=Ah, where A is constant cross-sectional areaAdd the two end faces and rectangular lateral faces
CylinderVr2hCurved area 2πrh; closed total 2πrh+2πr2
Right pyramidV=⅓AhBase area plus triangular faces; use slant heights where required
Right coneV=⅓πr2hCurved area πrl; closed total πrlr2
SphereV=4πr3/3Surface area 4πr2
HemisphereV=2πr3/3Curved area 2πr2; include base for total 3πr2

Compound solids require a construction plan: split the object into recognizable parts, decide whether to add or subtract, use a consistent unit and include only exposed surfaces. A joined circular face inside a cylinder-and-hemisphere model is not externally visible, so it should not be counted in total external surface area.

Worked example: cylinder with a hemispherical top

A tank has radius 3 m, cylindrical height 8 m and a hemispherical top. Its volume is π(3²)(8)+(2/3)π(3³)=72π+18π=90π m³. Its external area, excluding the base, is the cylinder’s curved area plus the hemisphere’s curved area: 2π(3)(8)+2π(3²)=48π+18π=66π m². The shared circular join is internal and must not be added.

Right and non-right triangles: choosing the correct method

Right triangles

Start by marking the right angle and choosing the reference angle. The hypotenuse is opposite the right angle, not merely the longest-looking side in a sketch. The labels opposite and adjacent depend on the selected angle. Use Pythagoras when two side lengths determine a third; use a trigonometric ratio when an acute angle connects the known and unknown sides.

sin θ = opposite/hypotenuse   |   cos θ = adjacent/hypotenuse   |   tan θ = opposite/adjacent

When finding an angle, use the appropriate inverse operation and report the result in the required unit. If the context is a triangle and your calculator produces an acute angle, check that it fits the diagram. Technology cannot detect that you labelled the wrong sides.

Non-right triangles

The sine rule is efficient when you know an opposite side-angle pair. The cosine rule is suited to side-angle-side data when finding the third side, or side-side-side data when finding an angle. The area formula ½ab sin C uses two sides and their included angle.

a/sin A = b/sin B = c/sin C
c2 = a2+b2−2ab cos C
K = ½ab sin C

Worked example: cosine rule and area

Two sides of a triangle are 8 cm and 11 cm, with included angle 52°. The opposite side is c=√(8²+11²−2(8)(11)cos52°)≈8.76 cm. Its area is ½(8)(11)sin52°≈34.7 cm². Both calculations use the same included angle; the side found by the cosine rule is opposite that angle.

Method-selection shortcut: right angle → Pythagoras or SOHCAHTOA; known opposite pair → sine rule; SAS or SSS → cosine rule; two sides plus included angle for area → ½ab sin C. Then check whether a second sine-rule triangle is possible.

The ambiguous case of the sine rule

The shared AA course extends the sine rule to the ambiguous case. It arises with side-side-angle data when the known angle is not between the two known sides. Because sin θ = sin(180°−θ), one inverse-sine value can correspond to two possible interior angles.

Suppose the calculation gives sin B=0.8. The calculator gives the reference value B1≈53.13°. A second possibility is B2=180°−53.13°≈126.87°. Test each against the remaining angle sum and the side-length ordering. A proposed triangle is invalid if the known angle plus B is at least 180°, or if the side-angle relationships contradict the data.

Worked example: two possible triangles

In triangle ABC, A=30°, a=7 and b=10. From the sine rule, sin B=10sin30°/7=5/7. Therefore B1≈45.58° or B2≈134.42°. Both leave a positive third angle: C1≈104.42° and C2≈15.58°. Consequently two triangles satisfy the data. A complete solution must report both, not only the calculator’s first inverse-sine answer.

Labelled diagrams, bearings, elevation and depression

Construction of a labelled diagram from a written statement is assessed mathematical thinking, not decoration. Mark north lines for bearings, horizontal lines for elevation or depression, right angles, equal lengths, known sides and the precise requested quantity. Avoid making the drawing look to scale if the data do not support that assumption.

Three-figure bearings are measured clockwise from north and written with three digits, such as 035° or 270°. When two locations have separate north lines, those lines are parallel; alternate and corresponding angles can reveal an interior triangle angle. An angle of elevation is measured upward from a horizontal at the observer. An angle of depression is measured downward from a horizontal and is often equal to an alternate interior angle at the lower object.

Worked example: bearing and sine rule

A boat travels 12 km from A on a bearing of 040°, then 18 km from B on a bearing of 130°. The back bearing from B to A is 220°, so the included angle ABC is 220°−130°=90°. The direct distance AC is therefore √(12²+18²)=6√13≈21.6 km. The bearing of C from A then requires a second angle calculation and correct clockwise measurement from north. The diagram prevents subtraction of the wrong bearings.

In extended questions, a good diagram also identifies dependencies. You may need to calculate a base distance before finding a height, or calculate an angle before applying the sine rule. Keep unrounded values in the calculator between stages to avoid accumulated error.

Radians, arc length and sector area

A radian measures angle through the ratio of arc length to radius. One full turn is 2π radians, a half turn is π and a quarter turn is π/2. The conversion relationship is 180°=π radians. To convert degrees to radians, multiply by π/180; to convert radians to degrees, multiply by 180/π.

θ radians = θ degrees × π/180
θ degrees = θ radians × 180/π

When θ is in radians, arc length and sector area take especially simple forms:

s=     and     Ar2θ

The formula conditions matter. If the given angle is 60°, convert it to π/3 before using s=rθ. Length units follow the radius; sector area uses the corresponding square units. For a major arc or major sector, the central angle is greater than π. For a segment, subtract a triangle area from the sector area for a minor segment; examine the diagram before choosing the operation.

Worked example: sector perimeter and area

A sector has radius 9 cm and angle 5π/12. Its arc length is 9(5π/12)=15π/4 cm. Its area is ½(9²)(5π/12)=135π/8 cm². The sector perimeter is not just the arc: it is 15π/4+18 cm because the two radii are also boundary edges.

Radian fluency becomes essential in calculus because derivatives and integrals of sine and cosine take their standard forms only when angles are measured in radians. Treat radians as a natural unit, not a degree conversion trick.

Unit circle definitions, exact values and quadrants

On the unit circle, the point reached by an angle θ has coordinates (cos θ, sin θ). Tangent is sin θ/cos θ whenever cos θ≠0. This definition extends trigonometry beyond acute triangles and explains signs, periodicity, symmetry and exact values.

Angle0π/6π/4π/3π/2
sin θ01/2√2/2√3/21
cos θ1√3/2√2/21/20
tan θ0√3/31√3undefined

Use the reference angle to obtain the magnitude, then use the quadrant to choose the sign. In quadrant I all three ratios are positive. In quadrant II sine is positive; in quadrant III tangent is positive; in quadrant IV cosine is positive. For example, cos(3π/4)=−√2/2 because the reference angle is π/4 and cosine is negative in quadrant II.

Useful symmetry and periodic relationships include cos(−x)=cos x, sin(−x)=−sin x, sin(x+2π)=sin x, cos(x+2π)=cos x and tan(x+π)=tan x. Rather than memorising isolated statements, locate the corresponding points or slopes on the unit circle.

Worked example: exact ratio from a quadrant

Given sin θ=3/5 and π/2<θ<π, θ lies in quadrant II, where cosine is negative. From sin²θ+cos²θ=1, cos²θ=1−9/25=16/25, so cos θ=−4/5. Then tan θ=(3/5)/(−4/5)=−3/4. The interval determines the sign that a square root alone cannot decide.

Pythagorean and double-angle identities

An identity is true for every value in its domain, whereas an equation is true only for particular solutions. To verify an identity, transform one side into the other without assuming the desired conclusion. Factor, find a common denominator or replace expressions using a known identity.

sin2 θ+cos2 θ=1
tan θ=sin θ/cos θ
sin 2θ=2sin θ cos θ
cos 2θ=cos2 θ−sin2 θ=2cos2 θ−1=1−2sin2 θ

The three cosine double-angle forms are equivalent. Choose the one that removes the unwanted function. If an expression contains only sin²θ, use cos2θ=1−2sin²θ; if it contains only cos²θ, use cos2θ=2cos²θ−1.

Worked example: simplify without finding the angle

If cos θ=4/5 and θ is acute, then sin θ=3/5. Therefore sin2θ=2(3/5)(4/5)=24/25 and cos2θ=2(4/5)²−1=32/25−1=7/25. A useful check is (24/25)²+(7/25)²=1.

Do not divide by a trigonometric expression without checking whether it could equal zero. Dividing an equation by sin x, for example, can lose solutions for which sin x=0. Factor and test zero factors separately.

Circular-function graphs and transformations

The functions sin x, cos x and tan x are periodic. Sine and cosine have period 2π and range [−1,1]. Tangent has period π, range all real numbers and vertical asymptotes where cos x=0. A sketch should show axes, scale, intercepts, extrema and asymptotes where relevant.

For f(x)=a sin(b(x+c))+d or the corresponding cosine model:

  • amplitude is |a|;
  • period is 2π/|b| when x is measured in radians;
  • horizontal shift is −c because the bracket is x+c;
  • vertical shift and midline are d and y=d;
  • maximum and minimum are d+|a| and d−|a|.

Worked example: analyse a sinusoidal model

For h(t)=4cos(π(t−2)/6)+7, the amplitude is 4, the midline is 7 and the period is 2π÷(π/6)=12. The range is [3,11]. Because the cosine input is zero at t=2, the graph has a maximum of 11 there. In a Ferris-wheel context, 7 may represent centre height and 4 the radius, while the model period is 12 time units.

Technology is valuable for checking windows, intersections and regression models, but a display can hide behaviour if the window is poorly chosen. Use algebra to predict amplitude, period and midline, then select a viewing interval that contains at least one full cycle.

Solving trigonometric equations in a finite interval

A complete answer must include every solution in the stated interval. The general process is: simplify; isolate a trigonometric ratio when possible; find reference values; generate all relevant quadrant solutions; use periodicity; and filter endpoints carefully. Degrees and radians must match both the interval and calculator mode.

Worked example: a basic finite interval

Solve 2sin x=1 for 0≤x≤2π. Then sin x=1/2. The reference angle is π/6, and sine is positive in quadrants I and II. Therefore x=π/6 or 5π/6. Adding 2π produces values outside the interval.

Worked example: a quadratic in cosine

Solve 2cos²x−cos x−1=0 for 0≤x≤2π. Let u=cos x. Then (2u+1)(u−1)=0, so cos x=−1/2 or cos x=1. The solutions are x=2π/3, 4π/3, 0 and 2π. Both endpoints are included and represent distinct interval values even though they occupy the same unit-circle point.

Worked example: use an identity first

Solve 2sin²x+5cos x+1=0. Replace sin²x with 1−cos²x: 2(1−cos²x)+5cos x+1=0. This becomes 2cos²x−5cos x−3=0 after multiplying by −1. Factor to (2cos x+1)(cos x−3)=0. The value cos x=3 is impossible, leaving cos x=−1/2. Finish using the requested interval.

Graphical solutions are also legitimate when requested or when technology is appropriate. Enter the two sides as separate functions and read all intersections inside the domain. State the solutions with suitable precision; a screenshot or unexplained list is not a mathematical argument.

Exact values, rounding and calculator discipline

Preserve π, radicals and fractions when an exact answer is requested. Avoid converting √3/2 or 5π/12 into a decimal too early. In multi-step geometry, store full calculator values or use an answer variable; rounding intermediate lengths can noticeably alter a final angle or surface area.

Before every trigonometric calculation, inspect the unit indicator. A degree-mode calculator evaluating sin(π/6) does not produce the intended radian value. After an inverse-trig result, compare its size with the diagram and determine whether another quadrant or ambiguous-case answer exists.

Write the equation before the decimal. A response such as “x=8.42” gives the examiner little evidence if the calculator entry was wrong. A labelled substitution into the sine rule, cosine rule or model communicates method and may earn credit even when arithmetic fails.

Exam strategy: a reliable geometry and trigonometry workflow

  1. Extract the geometry. Underline known lengths, angles, units, bearings and interval restrictions.
  2. Draw or redraw. Make a clean labelled diagram and identify right angles, projections, opposite pairs and included angles.
  3. Choose the relationship. State the formula symbolically before substituting.
  4. Check units and mode. Convert lengths and angle units; set degrees or radians deliberately.
  5. Calculate with full precision. Keep exact forms or stored values through intermediate stages.
  6. Generate all solutions. Test ambiguous triangles, quadrants, periodic copies and interval endpoints.
  7. Interpret. Reject negative lengths, impossible angles or values outside the physical and stated domains.
  8. Communicate. Add units, appropriate accuracy and a sentence answering the context.

Common mistakes and their repairs

MistakeWhy it failsRepair
Using degrees in s=rθThe compact formula assumes radiansConvert first using θraddegπ/180
Mismatching sine-rule pairsA side must match its opposite angleAnnotate opposite pairs in the diagram before writing ratios
Wrong cosine-rule angleThe angle must oppose the isolated sideWrite the side-angle correspondence explicitly
One inverse-sine answerA second supplementary angle may form a valid triangleTest 180°−θ and the angle sum
Counting hidden joined facesInternal faces are not part of external areaShade only the exposed boundary
Confusing slant and vertical heightVolume uses perpendicular height; cone area uses slant heightMark the right triangle linking them
Wrong phase shift signx+c shifts left by cFind where the bracket equals zero
Losing solutions by divisionDividing by sin x or cos x removes zero casesFactor and test every factor separately
Rounding earlyIntermediate error propagatesStore values and round only the final result
Unlabelled calculator outputIt does not demonstrate mathematical methodShow the model, equation and interval reasoning

How AA SL and AA HL expectations differ

AA HL students complete the shared SL content and then extend it. The additional higher-level topic introduces reciprocal ratios and their Pythagorean identities, inverse trigonometric functions with domains and ranges, further compound-angle and double-angle identities, symmetry properties, and vectors in two and three dimensions. Vector work then develops scalar and vector products, lines, planes, intersections and angles.

This page intentionally keeps the core formula guide focused on shared content. For the extension, continue to the AA HL-only geometry and trigonometry guide. Keeping the sequence clear helps SL students avoid unnecessary overload and helps HL students diagnose whether an error comes from foundational trigonometry or from an additional vector technique.

2029 course update: the IB states that the revised Mathematics: Analysis and Approaches course begins first teaching in August 2027 with first assessment in May 2029. This article reflects the officially published geometry and trigonometry sequence used for the current guide; students in the transition should follow their school’s assigned guide and session-specific formula booklet.

Fourteen-day geometry and trigonometry revision plan

DayFocusEvidence of mastery
1Prerequisite Pythagoras, SOHCAHTOA and unitsChoose ratios without topic labels and explain side names
23D distance and midpointExact coordinates and distance, checked geometrically
3Solids and compound volumeCorrect split, cubic units and internal-face decisions
4Surface area and line-plane anglesCorrect projection, slant height and exposed surfaces
5Sine ruleOpposite pairs labelled before substitution
6Cosine rule and triangle areaMethod selected from SAS, SSS or included-angle data
7Ambiguous caseEvery valid triangle reported and invalid cases rejected
8Bearings, elevation and diagramsAccurate north lines, horizontals and multi-stage plan
9Degrees, radians, arcs and sectorsConversions exact and sector perimeter distinguished from arc
10Unit circle and exact valuesReference angle plus quadrant sign, without decimal rescue
11IdentitiesTransform one side logically and state domain restrictions
12Graphs and transformationsAmplitude, period, midline, shift and range identified
13Finite-interval equationsAll quadrant, periodic and endpoint solutions included
14Mixed examination set and error logMethod chosen independently; repeated errors repaired

On each day, begin with two retrieval questions from earlier topics, study one worked example, complete several single-skill questions and finish with one mixed problem. Mark the work by error type: diagram, formula choice, algebra, exact value, calculator mode, interval or communication. Reattempt errors from a blank page after two days.

Geometry and trigonometry connect strongly to the AA SL and HL functions guide, especially transformations, inverse operations and graphical solutions. Algebraic manipulation from the Number and Algebra guide is equally important when identities or equations become quadratic.

Final mastery checklist

  • I can find distance and midpoint in three dimensions exactly.
  • I can extract a right triangle from a solid and identify a line’s projection.
  • I distinguish perpendicular height, slant height, curved area and total area.
  • I select between Pythagoras, right-triangle ratios, sine rule and cosine rule.
  • I test the ambiguous sine-rule case instead of accepting one inverse-sine value.
  • I construct labelled diagrams for bearings, elevation, depression and multi-stage geometry.
  • I convert degrees and radians and apply arc and sector formulas with correct units.
  • I derive exact values from reference angles and quadrant signs.
  • I use identities without cancelling possible zero solutions.
  • I read amplitude, period, phase shift, midline and range from a sinusoidal model.
  • I solve trigonometric equations completely within a finite interval.
  • I preserve exact values, use full precision and communicate a contextual final answer.

Frequently asked questions

Is this geometry and trigonometry content required for both AA SL and AA HL?

Yes. The standard-level Topic 3 sequence is studied by AA SL students and forms required foundation for AA HL students, who then add higher-level identities and vectors.

Are vectors included in the AA SL formula list?

No. Vector content belongs to the additional higher-level sequence. AA SL students still work with three-dimensional coordinates, distance, midpoint, solids and right-triangle geometry.

When should I use the sine rule instead of the cosine rule?

Use the sine rule when you know an opposite side-angle pair. Use the cosine rule for SAS when finding a side or SSS when finding an angle. Always check for the ambiguous case with suitable side-side-angle data.

Do arc length and sector area formulas require radians?

The compact forms s=rθ and A=½r²θ require θ in radians. Convert degree data first.

Are radians assumed in IB Math AA examinations?

The official guide states that radian measure should be assumed unless otherwise indicated. Read each question and calculator mode carefully.

Do I need exact trigonometric values?

Yes. Know the standard unit-circle values and derive related angles with reference angles and quadrant signs. Exact fractions, radicals and multiples of π are often required.

What is the ambiguous sine-rule case?

Because sin θ equals sin(180°−θ), side-side-angle data can produce zero, one or two valid triangles. Test the supplementary angle and the triangle angle sum.

How do I find an angle between a line and a plane?

Construct the perpendicular projection of the line onto the plane. The line, projection and perpendicular height form a right triangle; the requested angle lies between the line and projection.

How can I avoid losing solutions in trigonometric equations?

Do not divide by an expression that could equal zero without testing that case. Factor where possible, generate quadrant and periodic solutions, and filter only after comparing with the closed or open interval.

Is calculator graphing enough for a solution?

Technology can locate intersections and check work, but show the functions, interval, relevant algebra or interpretation, and solutions to suitable accuracy. An unexplained screenshot is not a complete mathematical argument.

What should an AA HL student study next?

Continue to the dedicated AA HL-only guide for reciprocal ratios, inverse trig functions, compound-angle identities and vector geometry.

Will the first-assessment-2029 course change this page?

The IB describes the update as refinement and has published a transition timeline. Students assessed in May 2029 or later should use the new guide and formula booklet assigned by their school; this page should be checked against that session’s official documents.

Official sources and related RevisionTown guides

This guide was checked against the official IB Mathematics: Analysis and Approaches guide, the IB Diploma mathematics overview and the official Mathematics AA course-update page.

Continue with Geometry and Trigonometry AA HL Only, Functions Formulae AA SL and HL, Number and Algebra Formulae AA SL and HL, or revisit Prior Learning Formulae AA SL and HL.

Editorial note: educational guide, independently written by RevisionTown. Always use your school’s official IB documents for your examination session. Last reviewed: 20 August 2026.

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