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Sums and Products of Roots – Vieta’s Formulas

Complete study guide on sums and products of roots (Vieta's Formulas). Covers quadratic, cubic & higher-degree polynomials with worked examples, practice quiz, and IB/A-Level exam tips.
"Sums and products of roots formula illustration showing Vieta's formulas for quadratic equations"
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Sums and Products of Roots

Master Vieta's Formulas — the powerful shortcut to find sums, products, and symmetric functions of polynomial roots without solving for each root individually.

📖 ~12 min read 📐 Worked Examples: 5 ✍️ Practice Questions: 6 🔁 Updated: March 2026

1. What Are Roots of a Polynomial?

A root (also called a zero) of a polynomial f(x) is any value of x for which f(x) = 0. Graphically, roots are the x-intercepts of the polynomial curve.

By the Fundamental Theorem of Algebra, every polynomial of degree n has exactly n roots in the complex number system, counting repeated roots with multiplicity.

📌 Key Terminology
  • Root / Zero: a value of x where f(x) = 0
  • Repeated Root: a root with multiplicity greater than 1
  • Real Roots: roots on the real number line
  • Complex Roots: roots of the form a + bi

Example: For f(x) = x² − 5x + 6 = (x − 2)(x − 3), the roots are 2 and 3.

2. Introducing Vieta's Formulas

Vieta's Formulas connect the coefficients of a polynomial directly to sums and products of its roots, without solving the polynomial explicitly.

💡 Core Idea

If a polynomial is written as f(x) = aₙ(x − r₁)(x − r₂)...(x − rₙ), then expanding and comparing coefficients gives identities for sums and products of roots.

🏛️ Historical Note

These identities are associated with François Viète and later generalized in broader algebraic work.

3. Quadratic Equations

Consider the quadratic equation:

ax² + bx + c = 0   (a ≠ 0)

Let the roots be α and β. Then:

a(x − α)(x − β) = ax² − a(α+β)x + aαβ

SUM OF ROOTS

α + β = −b/a

Negative second coefficient over leading coefficient

PRODUCT OF ROOTS

αβ = c/a

Constant term over leading coefficient

Special Case: Monic Quadratic (a = 1)

For x² + bx + c = 0:

  • Sum of roots: α + β = −b
  • Product of roots: αβ = c

This gives the standard monic form: x² − (α+β)x + αβ = 0

🔍 Show Full Derivation

Step 1: Expand the factored form:

a(x−α)(x−β) = a[x² − αx − βx + αβ] = ax² − a(α+β)x + aαβ

Step 2: Compare with ax² + bx + c:

  • −a(α+β) = b → α+β = −b/a
  • aαβ = c → αβ = c/a

4. Cubic Equations

For a cubic with roots α, β, γ:

ax³ + bx² + cx + d = 0   (a ≠ 0)

Vieta's Formulas for Cubics

SUM OF ALL ROOTS
α + β + γ
=
−b/a
SUM OF PRODUCTS OF PAIRS
αβ + βγ + αγ
=
c/a
PRODUCT OF ALL ROOTS
αβγ
=
−d/a
⚠️ Watch the Sign

For degree n, the product of all roots is (−1)ⁿ × a₀ / aₙ.

5. General Polynomial (Degree n)

For a degree-n polynomial with roots r₁, r₂, ..., rₙ:

f(x) = aₙxⁿ + aₙ₋₁xⁿ⁻¹ + aₙ₋₂xⁿ⁻² + ... + a₁x + a₀
Symmetric SumNotationFormula
Sum of all rootsr₁ + r₂ + ... + rₙ−aₙ₋₁ / aₙ
Sum of products of pairsΣ(rᵢrⱼ), i<jaₙ₋₂ / aₙ
Sum of triple productsΣ(rᵢrⱼrₖ), i<j<k−aₙ₋₃ / aₙ
Product of all rootsr₁r₂...rₙ(−1)ⁿ × a₀ / aₙ
📐 General Rule

The k-th elementary symmetric sum equals (−1)ᵏ × aₙ₋ₖ / aₙ.

6. Worked Examples

Example 1 — Finding Sum and Product Quadratic

Question: Without solving, find the sum and product of roots of 2x² − 7x + 3 = 0.

Here, a = 2, b = −7, c = 3.

Sum of roots = −b/a = 7/2

Product of roots = c/a = 3/2

Example 2 — Forming a Quadratic from Roots Quadratic

Question: Form a quadratic whose roots are 3 + √5 and 3 − √5.

Sum = 6

Product = 4

Equation: x² − 6x + 4 = 0

Example 3 — Finding α² + β² Derived Expression

Question: Given x² − 5x + 6 = 0, find α² + β².

α + β = 5, αβ = 6

α² + β² = (α + β)² − 2αβ = 25 − 12 = 13

Example 4 — Cubic with Unknown Coefficient Cubic

Question: The roots of x³ − 6x² + kx − 8 = 0 are α, β, γ and αβγ = 8. Find k.

By Vieta: α + β + γ = 6 and αβγ = 8.

Taking roots 2, 2, 2 gives the correct sum and product.

So αβ + βγ + αγ = 4 + 4 + 4 = 12, hence k = 12.

Example 5 — Roots of Related Equation New Roots

Question: If α, β are roots of 3x² − x − 2 = 0, find an equation with roots 1/α and 1/β.

α + β = 1/3 and αβ = −2/3

New sum = (α + β)/(αβ) = −1/2

New product = 1/(αβ) = −3/2

New equation: 2x² + x − 3 = 0

7. Forming Equations with New Roots

A major use of Vieta's Formulas is building new equations from transformed roots without explicitly solving the original equation.

Original rootsNew rootsNew SumNew Product
α, βα + k, β + k(α+β) + 2k(α+k)(β+k)
α, βkα, kβk(α+β)k²αβ
α, β1/α, 1/β(α+β)/αβ1/αβ
α, βα², β²(α+β)² − 2αβ(αβ)²
α, β−α, −β−(α+β)αβ
📝 General Method
  1. Let the new variable describe the new root relation.
  2. Express the old root in terms of the new variable.
  3. Substitute into the original equation and simplify.

8. Quick Reference Cheat Sheet

QUADRATIC

α + β = −b/a

αβ = c/a

CUBIC

α+β+γ = −b/a

αβ+βγ+αγ = c/a

αβγ = −d/a

IDENTITIES

α²+β² = (α+β)²−2αβ

α³+β³ = (α+β)³−3αβ(α+β)

(α−β)² = (α+β)²−4αβ

BUILD EQUATION

x² − Sx + P = 0

S = sum of roots, P = product

9. Practice Quiz

Test your understanding of sums and products of roots.

Question 1 — Quadratic Sum

For the equation 3x² + 12x − 9 = 0, what is the sum of the roots?

Question 2 — Quadratic Product

For 5x² − 3x + 10 = 0, what is the product of the roots?

Question 3 — Build from Roots

Which equation has roots 4 and −7?

Question 4 — Derived Expression

If α and β are roots of x² − 4x + 1 = 0, find α² + β².

Question 5 — Cubic

For 2x³ − x² + 3x − 5 = 0, find αβγ.

Question 6 — New Roots

If α, β are roots of x² − 6x + 4 = 0, what is the product of the new roots (α − 1) and (β − 1)?

0/6
Keep practising.

10. Frequently Asked Questions

Yes. Vieta's Formulas hold for real, complex, and repeated roots.
The product of n roots is (−1)ⁿ × (constant term)/(leading coefficient). That sign flips depending on whether n is even or odd.
They help you find expressions involving roots, construct related equations, and save time in algebra-heavy questions.
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