For any polynomial of form anxn + an−1xn−1 + ··· + a2x2 + a1x + a0 = 0:
Sum of roots


First we need to find out what both roots are. Let x1 = α, then x2 = 3α. Using formula we get:
Sum of roots: − 8/1
⇒ Thus: x1 + x2 = −8
α + 3α = −8
α = −2 = x1
x2 = 3 × −2 = −6
Understanding Roots of Quadratic Equations
For a standard quadratic equation in the form \(ax^2 + bx + c = 0\), where \(a, b, c\) are coefficients and \(a \neq 0\), it has two roots (solutions), often denoted by the Greek letters alpha (\(\alpha\)) and beta (\(\beta\)).
- The sum of the roots is \(\alpha + \beta\).
- The product of the roots is \(\alpha \times \beta\).
These values have a direct relationship with the coefficients of the quadratic equation.
For a quadratic equation \(ax^2 + bx + c = 0\), where \(a \neq 0\), the sum and product of its roots (\(\alpha, \beta\)) can be found using simple formulas derived from Vieta's formulas:
- Sum of roots (\(\alpha + \beta\)) = \(-\frac{b}{a}\)
- Product of roots (\(\alpha \times \beta\)) = \(\frac{c}{a}\)
You just need to identify the coefficients \(a, b,\) and \(c\) from your equation and plug them into these formulas.
If you are given the sum (S) and the product (P) of the roots, you can construct a quadratic equation using the following general form:
\(x^2 - (\text{Sum of roots})x + (\text{Product of roots}) = 0\)
So, the equation is:
\(x^2 - Sx + P = 0\)
Note that this gives you *one* such equation. Any equation \(k(x^2 - Sx + P) = 0\), where \(k\) is any non-zero constant, will have the same roots and thus the same sum and product.
Calculate Sum and Product
Enter the coefficients of the quadratic equation \(ax^2 + bx + c = 0\):