Pythagorean Theorem - Grade 8
1. The Pythagorean Theorem
Definition: In a right triangle, the square of the hypotenuse equals the sum of the squares of the two legs.
The Formula:
\( a^2 + b^2 = c^2 \)
Key Terms:
- Legs (a and b): The two sides that form the right angle
- Hypotenuse (c): The longest side, opposite the right angle
- Right triangle: A triangle with one 90° angle
Important Notes:
- The Pythagorean theorem ONLY works for right triangles
- The hypotenuse (c) is always the longest side
- The hypotenuse is always opposite the right angle
- The legs are the two shorter sides that form the right angle
Visual Representation:
In a right triangle with legs \( a \) and \( b \), and hypotenuse \( c \):
- The area of the square on leg \( a \) = \( a^2 \)
- The area of the square on leg \( b \) = \( b^2 \)
- The area of the square on hypotenuse \( c \) = \( c^2 \)
- Therefore: \( a^2 + b^2 = c^2 \)
2. Find the Length of the Hypotenuse
Formula:
\( c = \sqrt{a^2 + b^2} \)
where \( a \) and \( b \) are the legs, and \( c \) is the hypotenuse
Steps to Find the Hypotenuse:
- Square both leg lengths
- Add the squared values
- Take the square root of the sum
Examples:
Example 1: Find the hypotenuse if the legs are 3 and 4.
\( c^2 = a^2 + b^2 \)
\( c^2 = 3^2 + 4^2 \)
\( c^2 = 9 + 16 = 25 \)
\( c = \sqrt{25} = 5 \)
Example 2: Find the hypotenuse if the legs are 5 and 12.
\( c^2 = 5^2 + 12^2 = 25 + 144 = 169 \)
\( c = \sqrt{169} = 13 \)
Example 3: Find the hypotenuse if the legs are 6 and 8.
\( c^2 = 6^2 + 8^2 = 36 + 64 = 100 \)
\( c = \sqrt{100} = 10 \)
Example 4: Find the hypotenuse if the legs are 7 and 9.
\( c^2 = 7^2 + 9^2 = 49 + 81 = 130 \)
\( c = \sqrt{130} \approx 11.4 \)
3. Find the Missing Leg Length
Formulas:
\( a = \sqrt{c^2 - b^2} \)
or
\( b = \sqrt{c^2 - a^2} \)
Steps to Find a Missing Leg:
- Square the hypotenuse
- Square the known leg
- Subtract the squared leg from the squared hypotenuse
- Take the square root of the result
Examples:
Example 1: Find the missing leg if the hypotenuse is 10 and one leg is 6.
\( a^2 + b^2 = c^2 \)
\( a^2 + 6^2 = 10^2 \)
\( a^2 + 36 = 100 \)
\( a^2 = 100 - 36 = 64 \)
\( a = \sqrt{64} = 8 \)
Example 2: Find the missing leg if the hypotenuse is 13 and one leg is 5.
\( b^2 = c^2 - a^2 = 13^2 - 5^2 = 169 - 25 = 144 \)
\( b = \sqrt{144} = 12 \)
Example 3: Find the missing leg if the hypotenuse is 15 and one leg is 9.
\( a^2 = 15^2 - 9^2 = 225 - 81 = 144 \)
\( a = \sqrt{144} = 12 \)
Example 4: Find the missing leg if the hypotenuse is 20 and one leg is 16.
\( b^2 = 20^2 - 16^2 = 400 - 256 = 144 \)
\( b = \sqrt{144} = 12 \)
4. Find the Perimeter Using Pythagorean Theorem
Perimeter Formula:
\( P = a + b + c \)
Perimeter = sum of all three sides
Steps to Find Perimeter:
- Use the Pythagorean theorem to find the missing side
- Add all three sides together
Examples:
Example 1: Find the perimeter of a right triangle with legs 3 and 4.
Step 1: Find hypotenuse: \( c = \sqrt{3^2 + 4^2} = \sqrt{25} = 5 \)
Step 2: Add all sides: \( P = 3 + 4 + 5 = 12 \)
Example 2: Find the perimeter of a right triangle with legs 5 and 12.
Find hypotenuse: \( c = \sqrt{5^2 + 12^2} = \sqrt{169} = 13 \)
Perimeter: \( P = 5 + 12 + 13 = 30 \)
Example 3: Find the perimeter of a right triangle with hypotenuse 10 and one leg 6.
Find other leg: \( b = \sqrt{10^2 - 6^2} = \sqrt{64} = 8 \)
Perimeter: \( P = 6 + 8 + 10 = 24 \)
Example 4: Find the perimeter of a right triangle with legs 8 and 15.
Find hypotenuse: \( c = \sqrt{8^2 + 15^2} = \sqrt{289} = 17 \)
Perimeter: \( P = 8 + 15 + 17 = 40 \)
5. Pythagorean Theorem: Word Problems
Common Types of Word Problems:
- Ladder problems (ladder leaning against a wall)
- Distance problems (diagonal distance across a field)
- Screen size problems (TV or phone diagonal)
- Navigation problems (finding shortest distance)
- Sports problems (baseball diamond, soccer field)
Steps to Solve Word Problems:
- Read the problem carefully and identify the right triangle
- Label the known sides (legs or hypotenuse)
- Identify what you need to find
- Use the appropriate Pythagorean theorem formula
- Solve and include units in your answer
Examples:
Example 1 (Ladder Problem): A 25-foot ladder leans against a wall. The base of the ladder is 7 feet from the wall. How high up the wall does the ladder reach?
Identify: Ladder = hypotenuse (25 ft), base = one leg (7 ft), height = other leg (unknown)
\( h^2 = 25^2 - 7^2 = 625 - 49 = 576 \)
\( h = \sqrt{576} = 24 \) feet
Example 2 (Distance Problem): A person walks 12 meters east, then 5 meters north. How far are they from their starting point?
Identify: Forms a right triangle with legs 12 m and 5 m
\( c = \sqrt{12^2 + 5^2} = \sqrt{144 + 25} = \sqrt{169} = 13 \) meters
Example 3 (Screen Size): A rectangular TV screen is 24 inches wide and 18 inches tall. What is the diagonal measurement (screen size)?
\( d = \sqrt{24^2 + 18^2} = \sqrt{576 + 324} = \sqrt{900} = 30 \) inches
Example 4 (Baseball Diamond): A baseball diamond is a square with sides of 90 feet. What is the distance from home plate to second base?
Diagonal of square: \( d = \sqrt{90^2 + 90^2} = \sqrt{16200} \approx 127.3 \) feet
Example 5 (Ramp Problem): A wheelchair ramp is 20 feet long and rises 2 feet. How far is the base of the ramp from the building?
\( b = \sqrt{20^2 - 2^2} = \sqrt{400 - 4} = \sqrt{396} \approx 19.9 \) feet
6. Pythagorean Triples
Definition: A Pythagorean triple is a set of three positive integers \( a \), \( b \), and \( c \) that satisfy the equation \( a^2 + b^2 = c^2 \).
Common Pythagorean Triples:
Triple (a, b, c) | Verification |
---|---|
(3, 4, 5) | \( 3^2 + 4^2 = 9 + 16 = 25 = 5^2 \) ✓ |
(5, 12, 13) | \( 5^2 + 12^2 = 25 + 144 = 169 = 13^2 \) ✓ |
(8, 15, 17) | \( 8^2 + 15^2 = 64 + 225 = 289 = 17^2 \) ✓ |
(7, 24, 25) | \( 7^2 + 24^2 = 49 + 576 = 625 = 25^2 \) ✓ |
(9, 40, 41) | \( 9^2 + 40^2 = 81 + 1600 = 1681 = 41^2 \) ✓ |
(11, 60, 61) | \( 11^2 + 60^2 = 121 + 3600 = 3721 = 61^2 \) ✓ |
Multiples of Pythagorean Triples:
If \( (a, b, c) \) is a Pythagorean triple, then \( (ka, kb, kc) \) is also a Pythagorean triple for any positive integer \( k \).
Examples:
- From (3, 4, 5): multiply by 2 → (6, 8, 10)
- From (3, 4, 5): multiply by 3 → (9, 12, 15)
- From (5, 12, 13): multiply by 2 → (10, 24, 26)
Why Pythagorean Triples Are Useful:
- Provide quick answers without calculation
- Help identify right triangles immediately
- Used to check if answers are reasonable
- Save time on tests and homework
7. Converse of the Pythagorean Theorem
Statement: If \( a^2 + b^2 = c^2 \) for the sides of a triangle, then the triangle IS a right triangle.
Purpose:
The converse helps us determine whether a triangle with given side lengths is a right triangle.
Steps to Test if a Triangle is a Right Triangle:
- Identify the longest side (this would be the hypotenuse if it's a right triangle)
- Square all three sides
- Check if: (leg₁)² + (leg₂)² = (longest side)²
- If yes, it IS a right triangle. If no, it is NOT a right triangle
Three Cases:
Condition | Triangle Type |
---|---|
\( a^2 + b^2 = c^2 \) | Right Triangle |
\( a^2 + b^2 > c^2 \) | Acute Triangle |
\( a^2 + b^2 < c^2 \) | Obtuse Triangle |
Examples:
Example 1: Is a triangle with sides 9, 12, and 15 a right triangle?
Longest side = 15
Check: \( 9^2 + 12^2 = 15^2 \) ?
\( 81 + 144 = 225 \)
\( 225 = 225 \) ✓
Yes, it is a right triangle.
Example 2: Is a triangle with sides 5, 6, and 7 a right triangle?
Longest side = 7
Check: \( 5^2 + 6^2 = 7^2 \) ?
\( 25 + 36 = 49 \)
\( 61 \neq 49 \) ✗
No, it is NOT a right triangle.
Example 3: Is a triangle with sides 8, 15, and 17 a right triangle?
Check: \( 8^2 + 15^2 = 17^2 \) ?
\( 64 + 225 = 289 \)
\( 289 = 289 \) ✓
Yes, it is a right triangle. (This is a Pythagorean triple!)
Example 4: Is a triangle with sides 7, 10, and 12 a right triangle?
Check: \( 7^2 + 10^2 = 12^2 \) ?
\( 49 + 100 = 144 \)
\( 149 \neq 144 \) ✗
Since \( 149 > 144 \), this is an acute triangle.
8. Pythagorean Theorem and Distance Formula
Connection: The distance formula is derived from the Pythagorean theorem!
Distance Formula:
\( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \)
How It Works:
- Horizontal distance = \( |x_2 - x_1| \) (one leg)
- Vertical distance = \( |y_2 - y_1| \) (other leg)
- Diagonal distance = hypotenuse
- Apply Pythagorean theorem to find the diagonal
Example:
Find the distance between points \( A(1, 2) \) and \( B(4, 6) \).
Horizontal distance: \( |4 - 1| = 3 \)
Vertical distance: \( |6 - 2| = 4 \)
Distance: \( d = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \)
Quick Reference: Pythagorean Theorem Formulas
To Find | Formula |
---|---|
Pythagorean Theorem | \( a^2 + b^2 = c^2 \) |
Hypotenuse | \( c = \sqrt{a^2 + b^2} \) |
Leg (a or b) | \( a = \sqrt{c^2 - b^2} \) or \( b = \sqrt{c^2 - a^2} \) |
Perimeter | \( P = a + b + c \) |
Distance Formula | \( d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \) |
Common Pythagorean Triples to Memorize
(3, 4, 5) • (5, 12, 13) • (8, 15, 17) • (7, 24, 25)
💡 Key Tips for Pythagorean Theorem
- ✓ Only works for right triangles! Must have a 90° angle
- ✓ Hypotenuse (c) is ALWAYS the longest side opposite the right angle
- ✓ Legs (a and b) are the two sides forming the right angle
- ✓ Formula: \( a^2 + b^2 = c^2 \) — memorize this!
- ✓ When finding a leg: Subtract, then take square root
- ✓ When finding hypotenuse: Add, then take square root
- ✓ Memorize common Pythagorean triples: (3,4,5), (5,12,13), (8,15,17)
- ✓ Multiples also work: (6,8,10), (9,12,15), (15,20,25)
- ✓ Converse tests for right triangles: If \( a^2 + b^2 = c^2 \), it's a right triangle
- ✓ Always identify the longest side first when using converse
- ✓ In word problems, draw a diagram! It helps visualize the triangle
- ✓ Don't forget units in your final answer