



Math Concepts FAQs (Continuous Distributions & IVT)
Continuous Probability Distributions
What is a property of continuous probability distributions?
A key property of continuous probability distributions is that **the probability of a random variable taking on any single, exact value is zero.** That is, for any specific value 'a', P(X = a) = 0.
Why is the probability of a single value zero in continuous distributions?
In continuous distributions, probability is defined over intervals, represented by the area under the probability density function (PDF) curve. Since a single point on the x-axis has no width, the "area" above a single point is zero, hence the probability of the variable landing on any *exact* value is zero.
What does this property imply for inequalities like P(X ≤ a) vs P(X < a)?
Because the probability of a single value is zero, including or excluding the endpoint 'a' does not change the probability for a continuous variable. Therefore:
P(X ≤ a) = P(X < a)
P(X ≥ a) = P(X > a)
P(a ≤ X ≤ b) = P(a < X < b)
Intermediate Value Theorem (IVT)
What is the Intermediate Value Theorem (IVT)? What does it state?
The Intermediate Value Theorem is a fundamental theorem in calculus about the values that a continuous function can take. It states that if a function f
is continuous on a closed interval [a, b]
, and N
is any number between f(a)
and f(b)
(where f(a) ≠ f(b)
), then there must exist at least one number c
in the open interval (a, b)
such that f(c) = N
.
In simpler terms, if you can draw the graph of a continuous function between two points without lifting your pen, then the function must pass through every y-value between the y-values of those two points.
What are the conditions required for the Intermediate Value Theorem to apply?
The Intermediate Value Theorem has two essential conditions that must be met:
- The function
f
must be **continuous** on the closed interval[a, b]
. - The value
N
must be **between**f(a)
andf(b)
(not equal to either, unless f(a)=f(b)).
If either of these conditions is not met, the theorem does not guarantee the existence of the value c
.
How is the Intermediate Value Theorem used? (e.g., to find roots/zeros)
A common application of the IVT is to show that a function has a root (or zero) within a specific interval. To do this:
- Verify the function is continuous on the closed interval
[a, b]
. - Evaluate the function at the endpoints,
f(a)
andf(b)
. - If
f(a)
andf(b)
have opposite signs (one is positive and one is negative), then 0 is a value betweenf(a)
andf(b)
.
By the IVT, since 0 is between f(a)
and f(b)
, there must exist a value c
between a
and b
such that f(c) = 0
. This proves that a root exists within that interval.
When does the Intermediate Value Theorem NOT apply or guarantee a result?
The IVT's guarantee fails if the conditions are not met:
- **Discontinuous Function:** If the function is not continuous on the closed interval
[a, b]
, it might "jump" over the intermediate valueN
without ever reaching it. - **Value N is not between f(a) and f(b):** If N is greater than both f(a) and f(b) (or less than both), the theorem doesn't say anything about whether the function hits that value between 'a' and 'b'.
Also, the IVT **only guarantees existence**; it does not provide a method to find the exact value of 'c'.