Probability - Grade 8
1. Probability of Simple Events
Definition: The probability of a simple event is the chance that the event will occur. It's the ratio of favorable outcomes to total possible outcomes.
Formula:
\( P(A) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{n(A)}{n(S)} \)
Key Properties:
- Range: \( 0 \leq P(A) \leq 1 \)
- Impossible event: P(A) = 0
- Certain event: P(A) = 1
- Can be expressed as: Fraction, decimal, or percent
Examples:
Example 1: Rolling a 4 on a standard die
Favorable outcomes: 1 (only one 4)
Total outcomes: 6 (numbers 1-6)
\( P(\text{rolling 4}) = \frac{1}{6} \approx 0.167 \text{ or } 16.7\% \)
Example 2: Drawing a red card from a standard deck
Favorable: 26 (hearts and diamonds)
Total: 52 cards
\( P(\text{red card}) = \frac{26}{52} = \frac{1}{2} = 0.5 \text{ or } 50\% \)
2. Opposite, Mutually Exclusive, and Overlapping Events
Opposite Events (Complementary Events):
Two events are opposite if one event is "not" the other. They cover all possible outcomes.
\( P(A) + P(\text{not } A) = 1 \)
\( P(\text{not } A) = 1 - P(A) \)
Example: P(raining) and P(not raining) are opposite events
Mutually Exclusive Events:
Events that CANNOT happen at the same time. If one occurs, the other cannot.
\( P(A \text{ and } B) = 0 \)
\( P(A \text{ or } B) = P(A) + P(B) \)
- Example: Rolling a 3 or a 5 on one die (can't be both)
- Example: Turning left or right (can't do both)
Overlapping Events:
Events that CAN happen at the same time. They share some common outcomes.
\( P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B) \)
- Example: Drawing a card that is red OR a face card
- Some cards are both (red face cards), so we subtract the overlap
Example Problem:
In a deck of 52 cards, find P(red OR face card)
P(red) = 26/52, P(face card) = 12/52, P(red AND face card) = 6/52
\( P(\text{red OR face}) = \frac{26}{52} + \frac{12}{52} - \frac{6}{52} = \frac{32}{52} = \frac{8}{13} \)
3. Experimental Probability
Definition: Probability based on actual experiments or observations, not theoretical calculations.
Formula:
\( P(\text{event}) = \frac{\text{Number of times event occurred}}{\text{Total number of trials}} \)
Comparison:
Type | Theoretical Probability | Experimental Probability |
---|---|---|
Based on | Mathematical calculation | Actual experiments/data |
Formula | Favorable/Total possible | Times occurred/Total trials |
Example | P(heads) = 1/2 | Flipped 50 times, got 23 heads = 23/50 |
Example:
A basketball player shoots 80 free throws and makes 64 of them. What is the experimental probability of making a free throw?
\( P(\text{making free throw}) = \frac{64}{80} = \frac{4}{5} = 0.8 = 80\% \)
Key Point:
As the number of trials increases, experimental probability usually gets closer to theoretical probability.
4. Find Probabilities Using Two-Way Frequency Tables
Definition: A two-way frequency table shows data for two categories, organized in rows and columns.
Example Table:
Survey of 100 students about pets:
Has Dog | No Dog | Total | |
---|---|---|---|
Has Cat | 15 | 20 | 35 |
No Cat | 35 | 30 | 65 |
Total | 50 | 50 | 100 |
Finding Probabilities:
1. P(student has a dog):
\( P(\text{dog}) = \frac{50}{100} = \frac{1}{2} = 50\% \)
2. P(student has both cat and dog):
\( P(\text{cat and dog}) = \frac{15}{100} = \frac{3}{20} = 15\% \)
3. P(student has cat OR dog):
Total with at least one pet = 15 + 20 + 35 = 70
\( P(\text{cat or dog}) = \frac{70}{100} = 70\% \)
4. P(student has a cat GIVEN they have a dog): (Conditional probability)
\( P(\text{cat}|\text{dog}) = \frac{15}{50} = \frac{3}{10} = 30\% \)
5. Make Predictions Using Probability
Goal: Use probability to predict how many times an event will occur in a certain number of trials.
Formula:
\( \text{Expected number} = P(\text{event}) \times \text{Number of trials} \)
Steps:
- Find the probability of the event
- Multiply by the number of trials
- Round to a whole number if necessary
Examples:
Example 1: If you roll a die 60 times, how many times would you expect to roll a 3?
\( P(3) = \frac{1}{6} \)
Expected: \( \frac{1}{6} \times 60 = 10 \) times
Example 2: A basketball player makes 70% of free throws. In 40 attempts, how many are expected to go in?
Expected: \( 0.70 \times 40 = 28 \) free throws
Example 3: In a bag with 5 red and 3 blue marbles, if you draw 200 times (with replacement), how many blue marbles would you expect?
\( P(\text{blue}) = \frac{3}{8} \)
Expected: \( \frac{3}{8} \times 200 = 75 \) blue marbles
6. Compound Events: Find the Number of Outcomes
Definition: A compound event is an event that involves two or more simple events.
Methods to Count Outcomes:
1. Tree Diagram: Branch out all possibilities visually
2. List/Table: Write out all possible outcomes
3. Fundamental Counting Principle: Multiply the number of outcomes for each event
Example:
Flip a coin and roll a die. How many possible outcomes?
Coin outcomes: 2 (H or T)
Die outcomes: 6 (1, 2, 3, 4, 5, 6)
Total outcomes: 2 × 6 = 12
List: H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6
7. Compound Events: Find the Number of Sums
Common Problem: Rolling two dice and finding probabilities of different sums.
Two Dice Sum Table:
Die 1 ↓ / Die 2 → | 1 | 2 | 3 | 4 | 5 | 6 |
---|---|---|---|---|---|---|
1 | 2 | 3 | 4 | 5 | 6 | 7 |
2 | 3 | 4 | 5 | 6 | 7 | 8 |
3 | 4 | 5 | 6 | 7 | 8 | 9 |
Key Facts:
- Total outcomes: 6 × 6 = 36
- Possible sums: 2 through 12
- Most common sum: 7 (6 ways)
- Least common sums: 2 and 12 (1 way each)
Example:
P(sum = 7) when rolling two dice:
Ways to get 7: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) = 6 ways
\( P(\text{sum}=7) = \frac{6}{36} = \frac{1}{6} \)
8. Independent and Dependent Events
Independent Events:
Definition: The outcome of one event does NOT affect the outcome of the other.
\( P(A \text{ and } B) = P(A) \times P(B) \)
- Example: Flipping a coin and rolling a die
- Example: Drawing with replacement (put back and redraw)
- Example: Weather on different days
Dependent Events:
Definition: The outcome of one event DOES affect the outcome of the other.
\( P(A \text{ and } B) = P(A) \times P(B \text{ after } A) \)
- Example: Drawing without replacement (don't put back)
- Example: Choosing 2 people from a group
How to Identify:
Ask yourself: | Answer |
---|---|
Does first event change the second? | Yes → Dependent |
Is there replacement? | Yes → Independent; No → Dependent |
Are events completely separate? | Yes → Independent |
Examples:
Example 1 (Independent): Flip a coin twice. P(two heads)?
\( P(H) = \frac{1}{2} \), \( P(H) = \frac{1}{2} \)
\( P(HH) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} \)
Example 2 (Dependent): Bag has 5 red and 3 blue marbles. Draw 2 without replacement. P(both red)?
\( P(\text{1st red}) = \frac{5}{8} \)
\( P(\text{2nd red after 1st red}) = \frac{4}{7} \) (now 4 red left out of 7 total)
\( P(\text{both red}) = \frac{5}{8} \times \frac{4}{7} = \frac{20}{56} = \frac{5}{14} \)
9. Fundamental Counting Principle
Definition: If there are m ways to do one thing and n ways to do another, then there are m × n ways to do both.
Formula:
\( \text{Total outcomes} = n_1 \times n_2 \times n_3 \times ... \)
where \( n_1, n_2, n_3 \) are the number of choices for each event
When to Use:
- Making choices in sequence
- Finding total number of combinations
- When outcomes are independent
- When you need a quick count without listing
Examples:
Example 1: A restaurant offers 4 main dishes, 3 sides, and 2 desserts. How many different meal combinations?
Total = 4 × 3 × 2 = 24 different meals
Example 2: A password has 3 letters followed by 2 digits. How many possible passwords?
Letters: 26 choices each = 26 × 26 × 26
Digits: 10 choices each = 10 × 10
Total = 26 × 26 × 26 × 10 × 10 = 1,757,600 passwords
Example 3: How many 3-digit numbers can be formed using digits 1-5 without repetition?
1st digit: 5 choices
2nd digit: 4 choices (one already used)
3rd digit: 3 choices (two already used)
Total = 5 × 4 × 3 = 60 numbers
Quick Reference: Probability Formulas
Basic Probability:
\( P(A) = \frac{\text{favorable outcomes}}{\text{total outcomes}} \)
Complementary Events:
\( P(\text{not } A) = 1 - P(A) \)
Mutually Exclusive:
\( P(A \text{ or } B) = P(A) + P(B) \)
Overlapping Events:
\( P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B) \)
Independent Events:
\( P(A \text{ and } B) = P(A) \times P(B) \)
Dependent Events:
\( P(A \text{ and } B) = P(A) \times P(B \text{ after } A) \)
Counting Principle:
\( \text{Total} = n_1 \times n_2 \times n_3 \times ... \)
Expected Value:
\( \text{Expected} = P(\text{event}) \times \text{trials} \)
💡 Key Tips for Probability
- ✓ Probability always between 0 and 1 (or 0% and 100%)
- ✓ P(event) + P(not event) = 1
- ✓ Mutually exclusive: can't happen together (add probabilities)
- ✓ Overlapping: can happen together (subtract overlap)
- ✓ Independent: one doesn't affect other (multiply probabilities)
- ✓ Dependent: first affects second (multiply adjusted probability)
- ✓ With replacement = independent; Without = dependent
- ✓ Experimental probability based on actual results
- ✓ Two-way tables: use totals carefully
- ✓ Counting Principle: multiply all choices
- ✓ Tree diagrams help visualize compound events
- ✓ More trials = experimental closer to theoretical