Before you have learnt how to combine together different fractions to bring them under one denominator. However, sometimes you are required to do the opposite: split a fraction into distinct terms. In IB you will only be asked to split up fractions with two distinct linear terms in the denominator.
Solving partial fractions problems
![fraction](https://revisiontown.com/wp-content/uploads/2023/04/Screenshot-2023-04-20-at-3.29.03-AM-300x54.png)
- Determine which linear terms make up the denominator
x2 + x − 2 = (x − 1)(x + 2)
2. Equate the fraction to sum of two fractions with unknown constants as numerators and the linear terms as denominators
![fractions](https://revisiontown.com/wp-content/uploads/2023/04/Screenshot-2023-04-20-at-3.32.19-AM-300x68.png)
3. Multiply by the linear terms on both sides and determine the constant terms
![fractions](https://revisiontown.com/wp-content/uploads/2023/04/Screenshot-2023-04-20-at-3.32.27-AM-300x166.png)
4. Plug in constant terms into the original equation
![fractions](https://revisiontown.com/wp-content/uploads/2023/04/Screenshot-2023-04-20-at-3.32.35-AM-300x62.png)