Formula Sheets

Kinematic Formulas Physics

Kinematic Formulas Physics

Kinematic Formulas Physics

Complete Guide to Motion Equations & SUVAT Formulas

📐 Master the Mathematics of Motion

What Are Kinematic Formulas?

Kinematic formulas (also known as kinematic equations or SUVAT equations) are mathematical relationships that describe the motion of objects moving with constant acceleration. These fundamental equations are essential tools in physics for analyzing and predicting motion without considering the forces that cause it.

The term "SUVAT" comes from the five variables involved: S (displacement), U (initial velocity), V (final velocity), A (acceleration), and T (time). Understanding these equations is crucial for success in physics courses including IB Physics, AP Physics, GCSE Physics, and beyond.

These equations apply specifically to motion with constant (uniform) acceleration in a straight line. This includes free fall, projectile motion (analyzed in components), and many everyday situations involving cars, trains, and falling objects.

Understanding the SUVAT Variables

S - Displacement

Symbol: \(s\), \(\Delta x\), or \(d\)

Unit: meters (m)

Definition: The change in position from the starting point to the final point. It's a vector quantity with both magnitude and direction.

Note: Displacement differs from distance - it considers direction and can be negative.

U - Initial Velocity

Symbol: \(u\), \(v_0\), or \(v_i\)

Unit: meters per second (m/s)

Definition: The velocity of the object at the beginning of the time interval (at \(t = 0\)).

Note: If the object starts from rest, \(u = 0\).

V - Final Velocity

Symbol: \(v\) or \(v_f\)

Unit: meters per second (m/s)

Definition: The velocity of the object at the end of the time interval.

Note: This is what you're often trying to find in problems.

A - Acceleration

Symbol: \(a\)

Unit: meters per second squared (m/s²)

Definition: The rate of change of velocity. Must be constant for these equations to apply.

Note: Negative acceleration means slowing down or accelerating in the negative direction.

T - Time

Symbol: \(t\) or \(\Delta t\)

Unit: seconds (s)

Definition: The duration of motion - the time interval between initial and final states.

Note: Time is always positive in these equations.

The Five Kinematic Equations

💡 Key Insight: Each equation excludes one of the five SUVAT variables. Choose the equation that doesn't include the variable you're not given and don't need to find!

Equation 1: Final Velocity

\[ v = u + at \]

Variables Used: \(v\), \(u\), \(a\), \(t\)

Missing Variable: Displacement (\(s\))

Use When: You need to find final velocity and don't know or need displacement.

Physical Meaning: Final velocity equals initial velocity plus the change in velocity due to acceleration over time.

Equation 2: Displacement (Version 1)

\[ s = ut + \frac{1}{2}at^2 \]

Variables Used: \(s\), \(u\), \(a\), \(t\)

Missing Variable: Final velocity (\(v\))

Use When: You need to find displacement and don't know final velocity.

Physical Meaning: Displacement equals the distance traveled at initial velocity plus the additional distance from acceleration.

Equation 3: Displacement (Version 2)

\[ s = vt - \frac{1}{2}at^2 \]

Variables Used: \(s\), \(v\), \(a\), \(t\)

Missing Variable: Initial velocity (\(u\))

Use When: You know final velocity but not initial velocity.

Physical Meaning: Alternative form working backward from final velocity.

Equation 4: Velocity-Displacement Relationship

\[ v^2 = u^2 + 2as \]

Variables Used: \(v\), \(u\), \(a\), \(s\)

Missing Variable: Time (\(t\))

Use When: Time is unknown and not needed - very useful for free fall problems!

Physical Meaning: Relates velocity change to displacement and acceleration without involving time.

Equation 5: Average Velocity Method

\[ s = \frac{(u + v)}{2} \times t \]

Variables Used: \(s\), \(u\), \(v\), \(t\)

Missing Variable: Acceleration (\(a\))

Use When: You know both velocities but not acceleration.

Physical Meaning: Displacement equals average velocity multiplied by time (only valid for constant acceleration).

How Kinematic Equations Are Derived

Starting Point: Definition of Acceleration

All kinematic equations can be derived from the fundamental definition of acceleration:

\[ a = \frac{v - u}{t} \]

Rearranging this gives us Equation 1: \(v = u + at\)

Deriving Equation 2

For constant acceleration, displacement equals average velocity times time:

\[ s = \frac{u + v}{2} \times t \]

Substitute \(v = u + at\):

\[ s = \frac{u + (u + at)}{2} \times t = \frac{2u + at}{2} \times t \]

\[ s = ut + \frac{1}{2}at^2 \]

Deriving Equation 4

Starting with \(v = u + at\), solve for \(t\) and substitute into Equation 2:

\[ t = \frac{v - u}{a} \]

Substitute into \(s = ut + \frac{1}{2}at^2\):

After algebraic manipulation:

\[ v^2 = u^2 + 2as \]

Special Cases and Applications

Free Fall Motion

For objects falling under gravity alone (neglecting air resistance):

• Acceleration: \(a = g = 9.81 \text{ m/s}^2\) (downward)

• If dropped from rest: \(u = 0\)

• Distance fallen: \(s = \frac{1}{2}gt^2\)

• Velocity after falling height \(h\): \(v = \sqrt{2gh}\)

• Time to fall height \(h\): \(t = \sqrt{\frac{2h}{g}}\)

Projectile Motion

Projectile motion is analyzed by separating into horizontal and vertical components:

Horizontal Motion (x-direction):

• Acceleration: \(a_x = 0\) (no air resistance)

• Velocity: \(v_x = u_x = \text{constant}\)

• Displacement: \(x = u_x t\)

Vertical Motion (y-direction):

• Acceleration: \(a_y = -g = -9.81 \text{ m/s}^2\)

• Use all kinematic equations with \(a = -g\)

• \(v_y = u_y - gt\) and \(y = u_y t - \frac{1}{2}gt^2\)

Starting from Rest

When an object starts from rest (\(u = 0\)), the equations simplify:

\[ v = at \]

\[ s = \frac{1}{2}at^2 \]

\[ v^2 = 2as \]

\[ s = \frac{v}{2} \times t \]

Step-by-Step Problem Solving Strategy

Step 1: List Known Values

Write down all five SUVAT variables. Fill in what you know from the problem. Mark unknown values with "?".

Step 2: Identify Target

Determine which variable you need to find. This narrows down which equations might work.

Step 3: Choose Equation

Select the equation that contains your target variable and doesn't include the variable you don't know.

Step 4: Substitute & Solve

Plug in your known values and solve algebraically. Watch your signs (positive/negative)!

Step 5: Check Units

Verify that all units are consistent (SI units preferred). Convert if necessary before calculating.

Step 6: Verify Answer

Does your answer make physical sense? Is the magnitude reasonable? Is the sign correct?

Common Mistakes to Avoid

❌ Sign Errors

Problem: Mixing up positive and negative directions.

Solution: Define a positive direction at the start. Stick to it throughout. Upward is usually positive.

❌ Unit Inconsistencies

Problem: Mixing km/h with m/s, or using cm instead of m.

Solution: Convert everything to SI units (m, s, m/s, m/s²) before calculating.

❌ Using Wrong Equation

Problem: Choosing an equation that includes an unknown variable you don't need.

Solution: List all five variables first. Pick the equation without the "extra" unknown.

❌ Forgetting Squared Terms

Problem: Writing \(v = u^2 + 2as\) instead of \(v^2 = u^2 + 2as\).

Solution: Remember to square root when solving for velocity in this equation.

❌ Assuming Constant Velocity

Problem: Using \(s = vt\) when there's acceleration.

Solution: \(s = vt\) only works when \(a = 0\). Otherwise use kinematic equations.

❌ Confusing Distance and Displacement

Problem: Using total path length instead of straight-line displacement.

Solution: Remember \(s\) is displacement (vector), not total distance traveled.

Worked Example Problem

Problem:

A car accelerates from rest at 2.5 m/s² for 8 seconds. How far does it travel, and what is its final velocity?

Step 1: List Known Values

• \(u = 0\) m/s (starts from rest)

• \(a = 2.5\) m/s²

• \(t = 8\) s

• \(v = ?\) (need to find)

• \(s = ?\) (need to find)

Step 2: Find Final Velocity

Use: \(v = u + at\) (we have \(u\), \(a\), and \(t\))

\[ v = 0 + (2.5)(8) = 20 \text{ m/s} \]

Step 3: Find Displacement

Use: \(s = ut + \frac{1}{2}at^2\) (we have \(u\), \(a\), and \(t\))

\[ s = (0)(8) + \frac{1}{2}(2.5)(8)^2 \]

\[ s = 0 + 1.25 \times 64 = 80 \text{ m} \]

✓ Answer:

The car travels 80 meters and reaches a final velocity of 20 m/s.

Quick Reference Table

EquationVariables UsedMissing VariableWhen to Use
\(v = u + at\)\(v, u, a, t\)\(s\)Finding final velocity without displacement
\(s = ut + \frac{1}{2}at^2\)\(s, u, a, t\)\(v\)Finding displacement without final velocity
\(s = vt - \frac{1}{2}at^2\)\(s, v, a, t\)\(u\)Finding displacement without initial velocity
\(v^2 = u^2 + 2as\)\(v, u, a, s\)\(t\)When time is unknown or not needed
\(s = \frac{(u + v)}{2} \times t\)\(s, u, v, t\)\(a\)When acceleration is unknown or not needed

About the Author

Adam

Co-Founder @ RevisionTown

Math Expert specializing in various curricula including IB, AP, GCSE, IGCSE, and more

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