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Exponential Function Formula Example

Exponential Function Formula & Examples

1. Definition and Basic Formula

What is an Exponential Function?

An exponential function is a function in which the variable appears in the exponent. The general form is:

\[f(x) = a^x\]

where \(a > 0\) and \(a \neq 1\), and \(x\) is any real number.

The Natural Exponential Function

The most important exponential function uses Euler's number \(e\) as the base:

\[f(x) = e^x\]

where \(e \approx 2.71828...\)

2. General Forms of Exponential Functions

Standard Form

\[f(x) = a \cdot b^x\]
  • \(a\) = initial value (y-intercept)
  • \(b\) = base (growth/decay factor)
  • \(x\) = exponent (independent variable)

Exponential Growth Formula

When a quantity increases exponentially:

\[y = a(1 + r)^x\]
  • \(a\) = initial amount
  • \(r\) = growth rate (as a decimal)
  • \(x\) = time
  • Condition: \(r > 0\) (positive growth rate)

Exponential Decay Formula

When a quantity decreases exponentially:

\[y = a(1 - r)^x\]
  • \(a\) = initial amount
  • \(r\) = decay rate (as a decimal)
  • \(x\) = time
  • Condition: \(0 < r < 1\) (positive decay rate less than 1)

3. Exponential Function Rules

Laws of Exponents

  • \(a^0 = 1\) (Zero Exponent Rule)
  • \(a^{-x} = \frac{1}{a^x}\) (Negative Exponent Rule)
  • \(a^x \cdot a^y = a^{x+y}\) (Product Rule)
  • \(\frac{a^x}{a^y} = a^{x-y}\) (Quotient Rule)
  • \((a^x)^y = a^{xy}\) (Power of a Power Rule)
  • \(a^x \cdot b^x = (ab)^x\) (Product of Powers Rule)
  • \(\left(\frac{a}{b}\right)^x = \frac{a^x}{b^x}\) (Quotient of Powers Rule)

4. Worked Examples

Example 1: Population Growth

Problem: In 2010, there were 100,000 citizens in a town. If the population increases by 8% every year, then how many citizens will there be in 10 years? Round your answer to the nearest integer.

Solution:

Step 1: Identify the given information:
  • Initial population: \(a = 100,000\)
  • Growth rate: \(r = 8\% = 0.08\)
  • Time: \(x = 10\) years
Step 2: Use the exponential growth formula: \[f(x) = a(1 + r)^x\]
Step 3: Substitute the values: \[f(10) = 100,000(1 + 0.08)^{10}\] \[f(10) = 100,000(1.08)^{10}\]
Step 4: Calculate: \[f(10) = 100,000 \times 2.15892...\] \[f(10) \approx 215,892\]
Answer: The number of citizens in 10 years will be approximately 215,892.
Example 2: Simplifying Exponential Expressions

Problem: Simplify the exponential expression \(5^x - 5^{x+3}\).

Solution:

Step 1: Apply the product rule: \(a^{x+y} = a^x \cdot a^y\) \[5^{x+3} = 5^x \cdot 5^3 = 125 \times 5^x\]
Step 2: Substitute back: \[5^x - 5^{x+3} = 5^x - 125 \times 5^x\]
Step 3: Factor out \(5^x\): \[5^x - 125 \times 5^x = 5^x(1 - 125)\] \[= 5^x(-124)\] \[= -124 \cdot 5^x\]
Answer: The simplified form is \(-124 \cdot 5^x\).
Example 3: Solving Exponential Equations

Problem: Solve the equation \(4^3 \times 4^{x+5} = 4^{2x+12}\).

Solution:

Step 1: Apply the product rule on the left side: \[4^3 \times 4^{x+5} = 4^{3+x+5} = 4^{x+8}\]
Step 2: Now we have: \[4^{x+8} = 4^{2x+12}\]
Step 3: Since the bases are equal, equate the exponents: \[x + 8 = 2x + 12\]
Step 4: Solve for \(x\): \[x - 2x = 12 - 8\] \[-x = 4\] \[x = -4\]
Answer: \(x = -4\)
Example 4: Compound Interest

Problem: You invest $5,000 at an annual interest rate of 6% compounded annually. How much will you have after 8 years?

Solution:

Step 1: Use the compound interest formula (exponential growth): \[A = P(1 + r)^t\] where:
  • \(P = \$5,000\) (principal)
  • \(r = 0.06\) (6% interest rate)
  • \(t = 8\) years
Step 2: Substitute the values: \[A = 5,000(1 + 0.06)^8\] \[A = 5,000(1.06)^8\]
Step 3: Calculate: \[A = 5,000 \times 1.59385...\] \[A \approx \$7,969.24\]
Answer: After 8 years, you will have approximately $7,969.24.
Example 5: Radioactive Decay (Half-Life)

Problem: The half-life of a radioactive substance is 20 years. If you start with 80 grams, how much will remain after 60 years?

Solution:

Step 1: Use the half-life decay formula: \[A = A_0 \left(\frac{1}{2}\right)^{\frac{t}{h}}\] where:
  • \(A_0 = 80\) grams (initial amount)
  • \(t = 60\) years (time elapsed)
  • \(h = 20\) years (half-life)
Step 2: Substitute the values: \[A = 80 \left(\frac{1}{2}\right)^{\frac{60}{20}}\] \[A = 80 \left(\frac{1}{2}\right)^3\]
Step 3: Calculate: \[A = 80 \times \frac{1}{8}\] \[A = 10 \text{ grams}\]
Answer: After 60 years, 10 grams will remain.

5. Properties of Exponential Functions

  • Domain: All real numbers \((-\infty, \infty)\)
  • Range: All positive real numbers \((0, \infty)\)
  • Y-intercept: \((0, a)\) for \(f(x) = a \cdot b^x\)
  • Horizontal Asymptote: \(y = 0\) (the x-axis)
  • Increasing: If \(b > 1\), the function is increasing
  • Decreasing: If \(0 < b < 1\), the function is decreasing
  • One-to-one: Each x-value corresponds to exactly one y-value

6. Derivative and Integral

Derivative of Exponential Functions

For \(f(x) = e^x\):

\[\frac{d}{dx}(e^x) = e^x\]

For \(f(x) = a^x\):

\[\frac{d}{dx}(a^x) = a^x \ln a\]

Chain Rule for \(f(x) = e^{g(x)}\):

\[\frac{d}{dx}(e^{g(x)}) = g'(x) \cdot e^{g(x)}\]

Integral of Exponential Functions

For \(f(x) = e^x\):

\[\int e^x \, dx = e^x + C\]

For \(f(x) = a^x\):

\[\int a^x \, dx = \frac{a^x}{\ln a} + C\]

For \(f(x) = e^{ax}\):

\[\int e^{ax} \, dx = \frac{e^{ax}}{a} + C\]

7. Real-World Applications

Common Applications

  • Population Growth: Modeling increases in population over time
  • Compound Interest: Calculating investment growth
  • Radioactive Decay: Determining half-life of substances
  • Bacterial Growth: Tracking colony expansion
  • Carbon Dating: Estimating age of fossils and artifacts
  • Medicine: Drug concentration in bloodstream
  • Physics: Cooling and heating processes (Newton's Law of Cooling)
  • Economics: Inflation and depreciation calculations

Key Takeaway: Exponential functions model situations where the rate of change is proportional to the current value, leading to rapid growth or decay.

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