Compound Interest Formula: Complete Guide with Examples
Master compound interest calculations for exams, investments, and financial planning
A = P(1+r/n)nt
Standard Formula
5 Types
Compounding Frequencies
A = Pert
Continuous Compounding
What is Compound Interest?
Compound interest is the interest calculated on both the initial principal and the accumulated interest from previous periods. Unlike simple interest, which only calculates interest on the principal amount, compound interest creates exponential growth by earning "interest on interest." This powerful financial concept is fundamental for students studying mathematics, economics, and business, and appears frequently on standardized tests including SAT, AP, IB, GCSE, and A-Level examinations.
Key Difference: If you invest $1,000 at 5% for 20 years, simple interest earns $1,000 total, while compound interest earns $1,653.30—a difference of $653.30 purely from compounding.
Core Compound Interest Formulas
Standard Compound Interest Formula
A = Final amount (future value including principal and interest)
P = Principal amount (initial investment or loan)
r = Annual interest rate (in decimal form: 5% = 0.05)
n = Number of times interest is compounded per year
t = Time period in years
The compound interest (CI) alone can be calculated by subtracting the principal from the final amount:
Annual Compounding Formula
When interest is compounded once per year (n = 1), the formula simplifies to:
Use this formula when the problem states "compounded annually" or doesn't specify a compounding frequency.
Continuous Compounding Formula
Continuous compounding represents the theoretical maximum growth rate when interest is compounded infinitely often. This formula uses Euler's number (e ≈ 2.71828):
e = Euler's number (approximately 2.71828)
r = Annual interest rate (decimal)
t = Time in years
Use this formula when the problem explicitly states "compounded continuously."
Compounding Frequency Variations
The value of "n" (compounding frequency) dramatically affects the final amount. Here are the most common compounding periods:
| Compounding Type | Value of n | Formula | Common Use |
|---|---|---|---|
| Annually | n = 1 | \( A = P(1 + r)^t \) | Bonds, some savings accounts |
| Semi-annually | n = 2 | \( A = P(1 + r/2)^{2t} \) | Corporate bonds, some loans |
| Quarterly | n = 4 | \( A = P(1 + r/4)^{4t} \) | Most savings accounts, CDs |
| Monthly | n = 12 | \( A = P(1 + r/12)^{12t} \) | Mortgages, credit cards |
| Weekly | n = 52 | \( A = P(1 + r/52)^{52t} \) | Some short-term investments |
| Daily | n = 365 | \( A = P(1 + r/365)^{365t} \) | High-yield savings, some banks |
| Continuous | n → ∞ | \( A = Pe^{rt} \) | Theoretical maximum, some investments |
Step-by-Step Methodology
How to Solve Compound Interest Problems
Step 1: Identify the Variables
Read the problem carefully and extract: Principal (P), Interest rate (r), Time period (t), and Compounding frequency (n).
Step 2: Convert the Interest Rate
Convert the percentage rate to decimal form by dividing by 100. For example, 8% becomes 0.08.
Step 3: Select the Appropriate Formula
Choose the formula based on compounding frequency: standard formula for periodic compounding, or continuous formula if specified.
Step 4: Substitute and Calculate
Plug the values into the formula and solve. Use a scientific calculator for exponential calculations.
Step 5: Interpret the Result
Remember that A represents the total amount. Subtract P to find only the interest earned (CI).
Worked Example 1: Quarterly Compounding
Problem: Calculate the compound interest on $10,000 invested at 8% per annum for 3 years, compounded quarterly.
Solution:
Given: P = $10,000, r = 8% = 0.08, t = 3 years, n = 4 (quarterly)
Using the formula:
\[ A = 10000\left(1 + \frac{0.08}{4}\right)^{4 \times 3} \]
\[ A = 10000(1 + 0.02)^{12} \]
\[ A = 10000(1.02)^{12} \]
\[ A = 10000 \times 1.26824 \]
\[ A = \$12,682.40 \]
Compound Interest: CI = A - P = $12,682.40 - $10,000 = $2,682.40
Worked Example 2: Continuous Compounding
Problem: If $5,000 is invested at 6% annual interest compounded continuously for 10 years, what is the final amount?
Solution:
Given: P = $5,000, r = 6% = 0.06, t = 10 years
Using the continuous compounding formula:
\[ A = 5000 \times e^{0.06 \times 10} \]
\[ A = 5000 \times e^{0.6} \]
\[ A = 5000 \times 1.8221 \]
\[ A = \$9,110.50 \]
Compound Interest: CI = $9,110.50 - $5,000 = $4,110.50
Compound Interest vs Simple Interest
| Feature | Simple Interest | Compound Interest |
|---|---|---|
| Calculation Basis | Only on principal | On principal + accumulated interest |
| Formula | \( SI = \frac{P \times r \times t}{100} \) | \( A = P(1 + r/n)^{nt} \) |
| Growth Pattern | Linear (constant) | Exponential (accelerating) |
| Interest Amount | Same each period | Increases each period |
| Best for Borrowers | Yes (lower total interest) | No (higher total interest) |
| Best for Savers | No (lower returns) | Yes (higher returns) |
| Common Applications | Auto loans, short-term loans | Savings accounts, investments, credit cards |
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Key Formulas Summary
| Formula Type | Mathematical Expression | When to Use |
|---|---|---|
| General Compound Interest | \( A = P(1 + r/n)^{nt} \) | Any periodic compounding frequency |
| Annual Compounding | \( A = P(1 + r)^t \) | When n = 1 (once per year) |
| Continuous Compounding | \( A = Pe^{rt} \) | When compounding is continuous |
| Interest Only | \( CI = A - P \) | To find interest earned/paid |
| Present Value | \( P = \frac{A}{(1 + r/n)^{nt}} \) | To find initial investment needed |
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Disclaimer: This educational resource is designed to help students understand compound interest formulas for academic purposes, including preparation for SAT, AP, IB, GCSE, and A-Level examinations. While the mathematical formulas and examples are accurate, this content should not be considered professional financial advice. For specific investment or loan decisions, please consult with a qualified financial advisor. All examples use simplified scenarios for educational clarity.
Last Updated: January 25, 2026 | © RevisionTown
