Basic Math

Two-dimensional vectors | Twelfth Grade

Two-Dimensional Vectors

Complete Notes & Formulae for Twelfth Grade (Precalculus)

1. Vector Notation

Forms of Vectors:

Component Form:

\[ \vec{v} = \langle a, b \rangle \]

Unit Vector Form:

\[ \vec{v} = a\vec{i} + b\vec{j} \]

where \( \vec{i} = \langle 1, 0 \rangle \) and \( \vec{j} = \langle 0, 1 \rangle \)

2. Component Form of a Vector

Formula:

Given initial point \( P_1(x_1, y_1) \) and terminal point \( P_2(x_2, y_2) \):

\[ \vec{v} = \langle x_2 - x_1, y_2 - y_1 \rangle \]

The components represent horizontal and vertical displacement

Example:

Find component form: Initial point (2, 3), Terminal point (5, 7)

\( \vec{v} = \langle 5 - 2, 7 - 3 \rangle = \langle 3, 4 \rangle \)

3. Magnitude of a Vector

Formula:

For vector \( \vec{v} = \langle a, b \rangle \):

\[ |\vec{v}| = \|\vec{v}\| = \sqrt{a^2 + b^2} \]

The magnitude is the length of the vector (always non-negative)

Examples:

Find magnitude: \( \vec{v} = \langle 3, 4 \rangle \)

\( |\vec{v}| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \)

Find magnitude: \( \vec{v} = \langle -5, 12 \rangle \)

\( |\vec{v}| = \sqrt{(-5)^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13 \)

4. Direction Angle of a Vector

Formula:

For vector \( \vec{v} = \langle a, b \rangle \), the direction angle \( \theta \) is:

\[ \theta = \tan^{-1}\left(\frac{b}{a}\right) \]

⚠️ Must adjust for the correct quadrant!

Quadrant Adjustments:

QuadrantConditionAngle Formula
I\( a > 0, b > 0 \)\( \theta = \tan^{-1}(b/a) \)
II\( a < 0, b > 0 \)\( \theta = 180° + \tan^{-1}(b/a) \)
III\( a < 0, b < 0 \)\( \theta = 180° + \tan^{-1}(b/a) \)
IV\( a > 0, b < 0 \)\( \theta = 360° + \tan^{-1}(b/a) \)

5. Component Form from Magnitude and Direction

Formula:

Given magnitude \( |\vec{v}| = r \) and direction angle \( \theta \):

\[ \vec{v} = \langle r\cos\theta, r\sin\theta \rangle \]

or \( \vec{v} = r\cos\theta \vec{i} + r\sin\theta \vec{j} \)

Example:

Find component form: \( |\vec{v}| = 10 \), \( \theta = 60° \)

\( a = 10\cos(60°) = 10 \cdot \frac{1}{2} = 5 \)

\( b = 10\sin(60°) = 10 \cdot \frac{\sqrt{3}}{2} = 5\sqrt{3} \)

\( \vec{v} = \langle 5, 5\sqrt{3} \rangle \)

6. Add Vectors

Formula:

Add components separately:

\[ \vec{u} + \vec{v} = \langle a_1, b_1 \rangle + \langle a_2, b_2 \rangle = \langle a_1 + a_2, b_1 + b_2 \rangle \]

Graphical Methods:

Triangle Method (Head-to-Tail):

1. Draw first vector \( \vec{u} \)

2. Place tail of \( \vec{v} \) at head of \( \vec{u} \)

3. Resultant goes from tail of \( \vec{u} \) to head of \( \vec{v} \)

Parallelogram Method:

1. Draw both vectors from the same starting point

2. Complete the parallelogram

3. Resultant is the diagonal from the common starting point

Example:

Add: \( \vec{u} = \langle 2, 3 \rangle \) and \( \vec{v} = \langle 4, -1 \rangle \)

\( \vec{u} + \vec{v} = \langle 2 + 4, 3 + (-1) \rangle = \langle 6, 2 \rangle \)

7. Subtract Vectors

Formula:

\[ \vec{u} - \vec{v} = \langle a_1, b_1 \rangle - \langle a_2, b_2 \rangle = \langle a_1 - a_2, b_1 - b_2 \rangle \]

Or equivalently: \( \vec{u} - \vec{v} = \vec{u} + (-\vec{v}) \)

Example:

Subtract: \( \vec{u} = \langle 5, 7 \rangle \) and \( \vec{v} = \langle 2, 3 \rangle \)

\( \vec{u} - \vec{v} = \langle 5 - 2, 7 - 3 \rangle = \langle 3, 4 \rangle \)

8. Scalar Multiplication

Formula:

Multiply each component by the scalar:

\[ k\vec{v} = k\langle a, b \rangle = \langle ka, kb \rangle \]

Properties:

• Magnitude: \( |k\vec{v}| = |k| \cdot |\vec{v}| \)

• If \( k > 0 \): direction stays the same

• If \( k < 0 \): direction reverses (opposite)

• If \( k = 0 \): result is zero vector

Example:

Find: \( 3\vec{v} \) where \( \vec{v} = \langle 2, -4 \rangle \)

\( 3\vec{v} = 3\langle 2, -4 \rangle = \langle 6, -12 \rangle \)

Original magnitude: \( |\vec{v}| = \sqrt{4 + 16} = \sqrt{20} = 2\sqrt{5} \)

New magnitude: \( |3\vec{v}| = \sqrt{36 + 144} = \sqrt{180} = 6\sqrt{5} = 3(2\sqrt{5}) \)

9. Unit Vectors

Definition:

A unit vector has magnitude 1. To find the unit vector in the direction of \( \vec{v} \):

\[ \hat{v} = \frac{\vec{v}}{|\vec{v}|} = \frac{1}{|\vec{v}|}\vec{v} \]

Standard Unit Vectors:

\[ \vec{i} = \langle 1, 0 \rangle \quad \vec{j} = \langle 0, 1 \rangle \]

Example:

Find unit vector: \( \vec{v} = \langle 3, 4 \rangle \)

Magnitude: \( |\vec{v}| = \sqrt{9 + 16} = 5 \)

Unit vector: \( \hat{v} = \frac{1}{5}\langle 3, 4 \rangle = \langle \frac{3}{5}, \frac{4}{5} \rangle \)

Verify: \( |\hat{v}| = \sqrt{\frac{9}{25} + \frac{16}{25}} = \sqrt{\frac{25}{25}} = 1 \) ✓

10. Linear Combinations of Vectors

Definition:

A linear combination uses scalar multiplication and addition:

\[ \vec{w} = c_1\vec{v}_1 + c_2\vec{v}_2 \]

where \( c_1 \) and \( c_2 \) are scalars

Example:

Find: \( 2\vec{u} - 3\vec{v} \) where \( \vec{u} = \langle 4, 1 \rangle \) and \( \vec{v} = \langle 2, -3 \rangle \)

\( 2\vec{u} = 2\langle 4, 1 \rangle = \langle 8, 2 \rangle \)

\( 3\vec{v} = 3\langle 2, -3 \rangle = \langle 6, -9 \rangle \)

\( 2\vec{u} - 3\vec{v} = \langle 8, 2 \rangle - \langle 6, -9 \rangle = \langle 2, 11 \rangle \)

11. Quick Reference Summary

Essential Formulas:

Component Form: \( \vec{v} = \langle x_2 - x_1, y_2 - y_1 \rangle \)

Magnitude: \( |\vec{v}| = \sqrt{a^2 + b^2} \)

Direction: \( \theta = \tan^{-1}(b/a) \) (adjust for quadrant)

From Magnitude/Direction: \( \vec{v} = \langle r\cos\theta, r\sin\theta \rangle \)

Addition: \( \vec{u} + \vec{v} = \langle a_1 + a_2, b_1 + b_2 \rangle \)

Scalar Multiplication: \( k\vec{v} = \langle ka, kb \rangle \)

Unit Vector: \( \hat{v} = \frac{\vec{v}}{|\vec{v}|} \)

📚 Study Tips

✓ Always adjust direction angle based on which quadrant the vector is in

✓ Magnitude is always non-negative (like distance)

✓ Unit vectors have magnitude = 1

✓ Scalar multiplication changes magnitude, not direction (unless negative)

✓ Use head-to-tail method for adding vectors graphically

Shares: