Basic Math

Systems of equations | Twelfth Grade

Systems of Equations

Complete Notes & Formulae for Twelfth Grade (Precalculus)

1. Solve a System of Equations by Graphing

Method:

The solution to a system is the point where the graphs intersect

Steps:

1. Write each equation in slope-intercept form \( y = mx + b \)

2. Graph both lines on the same coordinate plane

3. Identify the point of intersection (x, y)

4. Verify the solution in both original equations

Example:

Solve by graphing:

\[ \begin{cases} y = 2x - 1 \\ y = -x + 5 \end{cases} \]

Both equations already in slope-intercept form

Graph both lines and find intersection point

Solution: (2, 3)

2. Classify a System of Equations

Types of Systems:

Consistent and Independent:

• Lines intersect at exactly ONE point

• Has one unique solution

• Different slopes: \( m_1 \neq m_2 \)

Consistent and Dependent:

• Same line (equations are equivalent)

• Infinitely many solutions

• Same slope and y-intercept: \( m_1 = m_2 \) and \( b_1 = b_2 \)

Inconsistent:

• Parallel lines (never intersect)

• No solution

• Same slope, different y-intercepts: \( m_1 = m_2 \) but \( b_1 \neq b_2 \)

Classification Table:

TypeGraphical ViewNumber of Solutions
Consistent IndependentLines intersect at one pointExactly one
Consistent DependentSame line (overlap)Infinitely many
InconsistentParallel linesNone

3. Solve Using Substitution

Steps:

1. Solve one equation for one variable (choose easiest)

2. Substitute that expression into the other equation

3. Solve for the remaining variable

4. Substitute back to find the other variable

Example:

Solve using substitution:

\[ \begin{cases} x + 2y = 7 \\ 3x - y = 5 \end{cases} \]

Solve first equation for x: \( x = 7 - 2y \)

Substitute into second: \( 3(7 - 2y) - y = 5 \)

Expand: \( 21 - 6y - y = 5 \)

Simplify: \( 21 - 7y = 5 \) → \( -7y = -16 \) → \( y = \frac{16}{7} \)

Substitute back: \( x = 7 - 2(\frac{16}{7}) = \frac{17}{7} \)

Solution: \( \left(\frac{17}{7}, \frac{16}{7}\right) \)

4. Solve Using Elimination

Steps:

1. Arrange equations in standard form \( ax + by = c \)

2. Multiply one or both equations to make coefficients opposite

3. Add or subtract equations to eliminate one variable

4. Solve for the remaining variable

5. Substitute back to find the other variable

Example:

Solve using elimination:

\[ \begin{cases} 2x + 3y = 8 \\ 3x - 3y = 12 \end{cases} \]

Notice: y-coefficients are already opposites (3 and -3)

Add equations: \( (2x + 3y) + (3x - 3y) = 8 + 12 \)

Simplify: \( 5x = 20 \) → \( x = 4 \)

Substitute x = 4 into first equation: \( 2(4) + 3y = 8 \)

Solve: \( 8 + 3y = 8 \) → \( y = 0 \)

Solution: (4, 0)

5. Solve Using Augmented Matrices

Augmented Matrix Form:

For system \( \begin{cases} ax + by = e \\ cx + dy = f \end{cases} \), write as:

\[ \left[\begin{array}{cc|c} a & b & e \\ c & d & f \end{array}\right] \]

Row Operations:

1. Swap rows: \( R_i \leftrightarrow R_j \)

2. Multiply row by constant: \( kR_i \)

3. Add multiple of one row to another: \( R_i + kR_j \)

Goal: Row-Echelon Form:

\[ \left[\begin{array}{cc|c} 1 & a & b \\ 0 & 1 & c \end{array}\right] \]

Ones on diagonal, zeros below

Example:

Solve: \( \begin{cases} 2x + y = 5 \\ x - y = 1 \end{cases} \)

Write augmented matrix: \( \left[\begin{array}{cc|c} 2 & 1 & 5 \\ 1 & -1 & 1 \end{array}\right] \)

\( R_1 \leftrightarrow R_2 \): \( \left[\begin{array}{cc|c} 1 & -1 & 1 \\ 2 & 1 & 5 \end{array}\right] \)

\( R_2 - 2R_1 \): \( \left[\begin{array}{cc|c} 1 & -1 & 1 \\ 0 & 3 & 3 \end{array}\right] \)

\( \frac{1}{3}R_2 \): \( \left[\begin{array}{cc|c} 1 & -1 & 1 \\ 0 & 1 & 1 \end{array}\right] \)

Read solution: \( y = 1 \), \( x - 1 = 1 \) → \( x = 2 \)

Solution: (2, 1)

6. Three Variables Using Substitution

General Form:

\[ \begin{cases} ax + by + cz = d \\ ex + fy + gz = h \\ ix + jy + kz = m \end{cases} \]

Steps:

1. Solve one equation for one variable

2. Substitute into the other two equations

3. Solve the resulting 2-variable system

4. Back-substitute to find all three variables

7. Three Variables Using Elimination

Strategy:

1. Choose a variable to eliminate

2. Use pairs of equations to eliminate that variable twice

3. Solve the resulting 2-variable system

4. Back-substitute to find all three variables

Example:

Solve:

\[ \begin{cases} x + y + z = 6 \\ 2x - y + z = 3 \\ x + 2y - z = 0 \end{cases} \]

Add equations 1 and 3 to eliminate z: \( 2x + 3y = 6 \)

Add equations 2 and 3 to eliminate z: \( 3x + y = 3 \)

Now solve 2-variable system for x and y

Then substitute back to find z

Solution: (1, \frac{4}{3}, \frac{11}{3})

8. Number of Solutions (Three Variables)

Three Possibilities:

One Unique Solution:

• Three planes intersect at exactly one point

• System is consistent and independent

• Ordered triple (x, y, z)

Infinitely Many Solutions:

• Three planes coincide (same plane)

• Or three planes intersect along a line

• System is consistent and dependent

• Solution expressed with parameters

No Solution:

• Planes don't all intersect at common point

• At least one pair is parallel or contradictory

• System is inconsistent

How to Determine:

• If you get a specific value for each variable → One solution

• If you get an identity (0 = 0) → Infinitely many solutions

• If you get a contradiction (0 = 5) → No solution

9. Word Problem Strategies

Steps for Word Problems:

1. Define variables: What are you solving for?

2. Write equations: Translate words into math

3. Solve the system: Use graphing, substitution, elimination, or matrices

4. Check and interpret: Does the answer make sense?

Common Types:

• Mixture problems (concentrations, solutions)

• Distance/rate/time problems

• Investment/interest problems

• Number problems

• Cost/revenue problems

10. Quick Reference Summary

Method Comparison:

MethodBest When...
GraphingVisual understanding needed, approximate solution OK
SubstitutionOne variable already isolated or easy to isolate
EliminationCoefficients line up well for adding/subtracting
MatricesLarge systems, calculator available, organized approach needed

📚 Study Tips

✓ Always check your solution in ALL original equations

✓ Substitution is best when one variable is already isolated

✓ Elimination is best when coefficients match or are easy to match

✓ Parallel lines mean no solution; same line means infinite solutions

✓ For 3 variables, eliminate same variable from two pairs of equations

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