Basic Math

Circles | Eleventh Grade

Circles

📌 What is a Circle?

A circle is the set of all points in a plane that are equidistant from a fixed point called the center. The distance from the center to any point on the circle is called the radius.

Equation Forms of a Circle

Standard Form (Center-Radius Form):

\( (x - h)^2 + (y - k)^2 = r^2 \)

Where:

  • \( (h, k) \) = center of the circle
  • \( r \) = radius of the circle
  • This form makes it easy to identify the center and radius

General Form (Expanded Form):

\( x^2 + y^2 + Dx + Ey + F = 0 \)

Where \( D, E, \) and \( F \) are constants. This form requires conversion to standard form to find center and radius.

Special Case - Circle at Origin:

\( x^2 + y^2 = r^2 \)

When the center is at the origin \( (0, 0) \), the equation simplifies significantly.

Finding the Center of a Circle

From Standard Form:

If the equation is \( (x - h)^2 + (y - k)^2 = r^2 \):

Center = \( (h, k) \)

⚠️ Important: Watch the signs! \( (x - h) \) means center x-coordinate is \( +h \), and \( (x + h) \) means center x-coordinate is \( -h \)

📝 Examples - Finding Center:

Example 1: \( (x - 3)^2 + (y - 5)^2 = 16 \)

Center: \( (3, 5) \)

Example 2: \( (x + 2)^2 + (y - 4)^2 = 25 \)

Rewrite: \( (x - (-2))^2 + (y - 4)^2 = 25 \)
Center: \( (-2, 4) \)

Example 3: \( x^2 + (y + 6)^2 = 9 \)

Rewrite: \( (x - 0)^2 + (y - (-6))^2 = 9 \)
Center: \( (0, -6) \)

Finding the Radius or Diameter

From Standard Form:

If the equation is \( (x - h)^2 + (y - k)^2 = r^2 \):

Radius:

\( r = \sqrt{r^2} \)

Take the square root of the right side

Diameter:

\( d = 2r \)

📝 Examples - Finding Radius and Diameter:

Example 1: \( (x - 1)^2 + (y + 3)^2 = 49 \)

\( r^2 = 49 \), so \( r = \sqrt{49} = 7 \)
Radius: 7
Diameter: \( 2(7) = 14 \)

Example 2: \( (x + 5)^2 + y^2 = 100 \)

\( r^2 = 100 \), so \( r = \sqrt{100} = 10 \)
Radius: 10
Diameter: 20

Example 3: \( x^2 + y^2 = 20 \)

\( r = \sqrt{20} = \sqrt{4 \cdot 5} = 2\sqrt{5} \approx 4.47 \)
Radius: \( 2\sqrt{5} \)
Diameter: \( 4\sqrt{5} \)

Writing Equations from Graphs

Steps:

  1. Identify the center \( (h, k) \) from the graph
  2. Find the radius by counting units from center to any point on the circle
  3. Square the radius to get \( r^2 \)
  4. Write the equation: \( (x - h)^2 + (y - k)^2 = r^2 \)

📝 Example - From Graph:

A circle has center at \( (2, -3) \) and passes through \( (2, 1) \). Write the equation.

Step 1: Center: \( (2, -3) \)
Step 2: Find radius using distance formula:
\( r = \sqrt{(2-2)^2 + (1-(-3))^2} = \sqrt{0 + 16} = 4 \)
Step 3: \( r^2 = 16 \)
Equation: \( (x - 2)^2 + (y + 3)^2 = 16 \)

Writing Equations Using Properties

Given Center and Radius:

Simply substitute the values into the standard form equation.

Given Endpoints of Diameter:

  1. Find the center using midpoint formula: \( \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right) \)
  2. Find the radius using distance from center to either endpoint
  3. Write the equation using center and radius

📝 Example - From Diameter Endpoints:

A circle has diameter with endpoints \( (2, 4) \) and \( (8, 12) \). Find the equation.

Step 1: Find center (midpoint):
\( h = \frac{2+8}{2} = 5, \quad k = \frac{4+12}{2} = 8 \)
Center: \( (5, 8) \)

Step 2: Find radius (distance from center to endpoint):
\( r = \sqrt{(5-2)^2 + (8-4)^2} = \sqrt{9+16} = \sqrt{25} = 5 \)

Equation: \( (x - 5)^2 + (y - 8)^2 = 25 \)

Converting from General to Standard Form

Method: Completing the Square

To convert \( x^2 + y^2 + Dx + Ey + F = 0 \) to standard form:

  1. Move the constant to the right side
  2. Group x-terms and y-terms separately
  3. Complete the square for x: add \( \left(\frac{D}{2}\right)^2 \) to both sides
  4. Complete the square for y: add \( \left(\frac{E}{2}\right)^2 \) to both sides
  5. Factor perfect square trinomials
  6. Simplify to get standard form

📝 Example - Completing the Square:

Convert \( x^2 + y^2 - 6x + 4y - 12 = 0 \) to standard form

Step 1: Move constant:
\( x^2 + y^2 - 6x + 4y = 12 \)

Step 2: Group terms:
\( (x^2 - 6x) + (y^2 + 4y) = 12 \)

Step 3: Complete the square for x:
Half of -6 is -3, squared is 9
\( (x^2 - 6x + 9) + (y^2 + 4y) = 12 + 9 \)

Step 4: Complete the square for y:
Half of 4 is 2, squared is 4
\( (x^2 - 6x + 9) + (y^2 + 4y + 4) = 12 + 9 + 4 \)

Step 5: Factor:
\( (x - 3)^2 + (y + 2)^2 = 25 \)

Center: \( (3, -2) \), Radius: 5

📝 Example 2 - More Practice:

Convert \( x^2 + y^2 + 8x - 2y + 8 = 0 \)

Move constant: \( x^2 + y^2 + 8x - 2y = -8 \)
Group: \( (x^2 + 8x) + (y^2 - 2y) = -8 \)
For x: \( \left(\frac{8}{2}\right)^2 = 16 \)
For y: \( \left(\frac{-2}{2}\right)^2 = 1 \)
\( (x^2 + 8x + 16) + (y^2 - 2y + 1) = -8 + 16 + 1 \)
\( (x + 4)^2 + (y - 1)^2 = 9 \)

Center: \( (-4, 1) \), Radius: 3

Finding Properties from General Form

Formulas from \( x^2 + y^2 + Dx + Ey + F = 0 \):

Center:

\( \left(-\frac{D}{2}, -\frac{E}{2}\right) \)

Radius:

\( r = \sqrt{\left(\frac{D}{2}\right)^2 + \left(\frac{E}{2}\right)^2 - F} \)

📝 Example - Direct from General Form:

Find center and radius of \( x^2 + y^2 - 10x + 6y + 9 = 0 \)

\( D = -10, E = 6, F = 9 \)

Center:
\( h = -\frac{-10}{2} = 5 \)
\( k = -\frac{6}{2} = -3 \)
Center: \( (5, -3) \)

Radius:
\( r = \sqrt{\left(\frac{-10}{2}\right)^2 + \left(\frac{6}{2}\right)^2 - 9} \)
\( = \sqrt{25 + 9 - 9} = \sqrt{25} = 5 \)

Graphing Circles

Step-by-Step Graphing:

  1. Convert to standard form if necessary
  2. Identify the center \( (h, k) \) and plot it
  3. Identify the radius \( r \)
  4. Plot four key points by moving \( r \) units:
    • Up from center: \( (h, k + r) \)
    • Down from center: \( (h, k - r) \)
    • Right from center: \( (h + r, k) \)
    • Left from center: \( (h - r, k) \)
  5. Draw a smooth circle through these four points

📝 Example - Complete Graphing:

Graph \( (x - 2)^2 + (y + 1)^2 = 16 \)

Step 1: Identify center and radius
Center: \( (2, -1) \)
Radius: \( r = \sqrt{16} = 4 \)

Step 2: Plot center at \( (2, -1) \)

Step 3: Plot four key points:
Up: \( (2, -1 + 4) = (2, 3) \)
Down: \( (2, -1 - 4) = (2, -5) \)
Right: \( (2 + 4, -1) = (6, -1) \)
Left: \( (2 - 4, -1) = (-2, -1) \)

Step 4: Draw smooth circle through these points

📝 Example 2 - From General Form:

Graph \( x^2 + y^2 - 4x + 6y - 3 = 0 \)

Step 1: Convert to standard form:
\( (x^2 - 4x) + (y^2 + 6y) = 3 \)
\( (x^2 - 4x + 4) + (y^2 + 6y + 9) = 3 + 4 + 9 \)
\( (x - 2)^2 + (y + 3)^2 = 16 \)

Step 2: Center: \( (2, -3) \), Radius: 4

Step 3: Key points:
\( (2, 1) \), \( (2, -7) \), \( (6, -3) \), \( (-2, -3) \)

Step 4: Draw the circle

⚡ Quick Summary

PropertyFormula
Standard Form\( (x-h)^2 + (y-k)^2 = r^2 \)
General Form\( x^2 + y^2 + Dx + Ey + F = 0 \)
Center\( (h, k) \)
Radius\( r = \sqrt{r^2} \)
Diameter\( d = 2r \)
  • Standard form makes it easy to identify center and radius
  • Watch signs carefully: \( (x - h) \) means center at \( +h \)
  • Use completing the square to convert general to standard form
  • All points on a circle are exactly \( r \) units from the center
  • To graph: plot center, mark 4 key points, draw smooth curve

📚 Key Formulas Reference

Distance Formula (for radius):

\( r = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \)

Midpoint Formula (for center from diameter):

\( \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right) \)

Completing the Square:

For \( x^2 + bx \), add \( \left(\frac{b}{2}\right)^2 \) to both sides

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